sql语句 函数 单行函数:一条记录返回一个结果 多行函数 组函数 聚合函数 (重点) :多条记录 返回一 个结果 (重点) 单行函数 日期函数: sysdate/current_date 以date类型返回当前的日期 add_months(d,x) 返回加上x月后的日期d的值 LAST_DAY(d) 返回的所在月份的最后一天 months_between(date1,date2) 返回...
SQL 複製 -- DOES NOT ACCOUNT FOR LEAP YEARS DECLARE @date1 DATETIME, @date2 DATETIME, @result VARCHAR(100); DECLARE @years INT, @months INT, @days INT, @hours INT, @minutes INT, @seconds INT, @milliseconds INT; SET @date1 = '1900-01-01 00:00:00.000' SET @date2 = '2018-12...
SQL Server DATEDIFF function returns the difference in seconds, minutes, hours, days, weeks, months, quarters and years between 2 datetime values. Quick Example: -- The difference is days between today and yesterday SELECT DATEDIFF(dd, GETDATE(
考虑使用 SQL Server 函数来计算两个日期(以月为单位)之间的差额: SQL Server: --DifferencebetweenOct02,2011andJan01,2012inmonthsSELECTDATEDIFF(month,'2011-10-02','2012-01-01');--Result:3 在PostgreSQL 中,您可以将年份之间的差值乘以 12,然后将月份部分之间的差值相加(可以为负)。
The above snippet illustrates that the difference between the provided dates is “1 year 10 months and 3 days”. Conclusion In databases, such as SQL Server, Oracle, etc., the DATEDIFF function is used to find the difference between provided Dates or TIMESTAMPS. However, Postgres doesn’t ...
The SQL statement SELECT DATEDIFF (month, '2000-01-31 23:59:59.000','2000-02-01 00:00:00.000');produces the following result: 1Even though the actual difference between the two datetime values is 1 second, the DATEDIFF function returns 1 when we ask for the difference in months. This ...
SQL -- DOES NOT ACCOUNT FOR LEAP YEARSDECLARE@date1ASDATETIME, @date2ASDATETIME, @resultASVARCHAR(100);DECLARE@yearsASINT, @monthsASINT, @daysASINT, @hoursASINT, @minutesASINT, @secondsASINT, @millisecondsASINT;SET@date1 ='1900-01-01 00:00:00.000';SET@date2 ='2018-12-12 07:08:01.123...
SQL -- DOES NOT ACCOUNT FOR LEAP YEARSDECLARE@date1ASDATETIME, @date2ASDATETIME, @resultASVARCHAR(100);DECLARE@yearsASINT, @monthsASINT, @daysASINT, @hoursASINT, @minutesASINT, @secondsASINT, @millisecondsASINT;SET@date1 ='1900-01-01 00:00:00.000';SET@date2 ='2018-12-12 07:08:01.123...
SQL复制 -- DOES NOT ACCOUNT FOR LEAP YEARSDECLARE@date1ASDATETIME, @date2ASDATETIME, @resultASVARCHAR(100);DECLARE@yearsASINT, @monthsASINT, @daysASINT, @hoursASINT, @minutesASINT, @secondsASINT, @millisecondsASINT;SET@date1 ='1900-01-01 00:00:00.000';SET@date2 ='2018-12-12 07:08:01...
SQL Kopieren SELECT DATEDIFF(millisecond, GETDATE(), SYSDATETIME()); D: Angeben von skalaren Unterabfragen und skalaren Funktionen für startdate und enddateIn diesem Beispiel werden skalare Unterabfragen und skalare Funktionen als Argumente für startdate und enddate verwendet....