考虑使用 SQL Server 函数来计算两天之间的日期差: SQL Server: --DifferencebetweenDec29,201123:00andDec31,201101:00indaysSELECTDATEDIFF(day,'2011-12-29 23:00:00','2011-12-31 01:00:00');--Result:2 请注意,DATEDIFF 返回了 2 天,尽管 datetime 值之间只有 1 天 2 小时。
在SQL Server中,可以使用T-SQL DATEDIFF()函数返回两个日期之间的差异。它适用于任何可以解析为time、date、smalldatetime、datetime、datetime2或datetimeoffset值的表达式。因此,你也可以得到两次的差值。 DATEDIFF()函数语法如下: DATEDIFF ( datepart , startdate , enddate ) AI代码助手复制代码 其中datepart是你想要...
返回新的 datetime 值 dateadd(datepart,number,date) 注： datepart : year（yy, yyyy...
我们来看一下这个日期差计算的官方描述,(下面这个是怎么出来的): hive> desc function extended datediff; //*查函数功能*// OK datediff(date1, date2) - Returns the number of days between date1 and date2 date1 and date2 are strings in the for 05 hive计算日期差函数datediff,hive修改日期连接符...
SQL Server DATEDIFF function returns the difference in seconds, minutes, hours, days, weeks, months, quarters and years between 2 datetime values. Quick Example: -- The difference is days between today and yesterday SELECT DATEDIFF(dd, GETDATE(
SQL 複製 USE AdventureWorks2022; GO SELECT DATEDIFF(day, '2007-05-07 09:53:01.0376635', GETDATE() + 1) AS NumberOfDays FROM Sales.SalesOrderHeader; GO USE AdventureWorks2022; GO SELECT DATEDIFF( day, '2007-05-07 09:53:01.0376635', DATEADD(day, 1, SYSDATETIME()) ) AS NumberOfDays ...
var Ypro = db.表.Count(e => SqlFunctions.DateDiff("dd", 添加的日期, day) == 1); //本周新增 //周一 DateTime dt1 = DateTime.Now.AddDays(0 - DateTime.Now.DayOfWeek); //周日 DateTime dt2 = dt1.AddDays(7); var Npro = from c in db.XX.ToList() ...
The result is <expression1> - <expression2> and the unit is in days. DATEDIFF Examples in MySQLExample 1The SQL statement, SELECT DATEDIFF ('2000-01-10', '2000-01-05');produces the following result: 5This is because 2000-01-10 is 5 days after 2000-01-05. ...
SQL -- DOES NOT ACCOUNT FOR LEAP YEARSDECLARE@date1ASDATETIME, @date2ASDATETIME, @resultASVARCHAR(100);DECLARE@yearsASINT, @monthsASINT, @daysASINT, @hoursASINT, @minutesASINT, @secondsASINT, @millisecondsASINT;SET@date1 ='1900-01-01 00:00:00.000';SET@date2 ='2018-12-12 07:08:01.123...
SQL复制 -- DOES NOT ACCOUNT FOR LEAP YEARSDECLARE@date1ASDATETIME, @date2ASDATETIME, @resultASVARCHAR(100);DECLARE@yearsASINT, @monthsASINT, @daysASINT, @hoursASINT, @minutesASINT, @secondsASINT, @millisecondsASINT;SET@date1 ='1900-01-01 00:00:00.000';SET@date2 ='2018-12-12 07:08:01...