119 Sum<<<BLOCK_data,THREAD_data,THREAD_data*sizeof (int)>>> (gpudata,result); 120 121 // 在内存中为计算对象开辟空间 122 int *sumArray = new int[BLOCK_data]; 123 // 从显存获取处理的结果 124 cudaMemcpy (sumArray, result, sizeof(int)*BLOCK_data, cudaMemcpyDeviceToHost); 125 126...
SumArray<<<BLOCKS_PerGrid, THREADS_PerBlock>>>(dev_c, dev_a);//, dev_b); // cudaDeviceSynchronize waits for the kernel to finish, and returns // any errors encountered during the launch. //等待全部线程运行结束 cudaStatus = cudaDeviceSynchronize(); if (cudaStatus != cudaSuccess) { f...
data_length)).astype(np.float32)print(arr)arr_cuda=cuda.to_device(arr)np_time=0.0nb_time=0.0foriinrange(100):res=np.array([0],dtype=np.float32)res_cuda=cuda.to_device(res)time0=time.time()ReducedSum[(data_length,data_length),(1,1)](arr_cuda,res_cuda)time1=time.time()res=re...
Q: How do I compute the sum of an array of numbers on the GPU? This is known as a parallel reduction operation. See the "reduction" sample for more details.Q: How do I output a variable amount of data from each thread? This can be achieved using a parallel prefix sum (also ...
(h_B); // part 2: using zerocopy memory for array A and B // allocate zerocpy memory CHECK(cudaHostAlloc((void **)&h_A, nBytes, cudaHostAllocMapped)); CHECK(cudaHostAlloc((void **)&h_B, nBytes, cudaHostAllocMapped)); // initialize data at host side initialData(h_A, nElem)...
9 CUDA: how to sum all elements of an array into one number within the GPU? 0 nccl - can we sum up all the values of an array on 1 device GPU to obtain the sum? 0 Summing up elements in array using managedCuda 1 sum vectors values with cuda C++ Hot Network Questions When ...
我们分别在host和device执行两个array相加,结果显示相同。 所有代码都可在我的仓库中获取GitHub - doorteeth/learn_cuda 大部分代码与《CUDA ® C Programming》类似,但是我会根据文章内容一些修改。大佬们,也可以去看看原文代码,谭升大佬的https://github.com/Tony-Tan/CUDA_Freshman也不错。
__global__ void SumArray(int *c, int *a)//, int *b){ __shared__ unsigned int mycache[THREADS_PerBlock];//设置每个块内同享内存threadsPerBlock==blockDim.x int i = threadIdx.x+blockIdx.x*blockDim.x;int j = gridDim.x*blockDim.x;//每个grid⾥⼀共有多少个线程 int cacheN;uns...
The host generates a 32-item array with randomly initialized floating point values. Only threads in the warp with itsid==1should add to the sum. However, the result from the device is wrong. An example output: EXPECTED:16.1606; ACTUAL:2.51008 ...
x * sizeof(int)); int * tmp = (int*)malloc(bytes); //initialize the array initialData_int(idata_host, size); memcpy(tmp, idata_host, bytes); double timeStart, timeElaps; int gpu_sum = 0; // device memory int * idata_dev = NULL; int * odata_dev = NULL; CHECK(cudaMalloc(...