publicclassSolution {publicbooleancanFinish(intnumCourses,int[][] prerequisites) {int[][] num =newint[numCourses][numCourses];for(inti = 0; i < prerequisites.length; i++){ num[prerequisites[i][0]][prerequisites[i][1]] = 1; }int[] finish =newint[numCourses];booleanflag =false;while...
所以,第一步要先将给出的矩阵,换算出邻接矩阵(也可以是邻接链表),然后再步步进行。 代码: publicclassSolution {publicbooleancanFinish(intnumCourses,int[][] prerequisites) {int[] indegree =newint[numCourses];int[][] matrix =newint[numCourses][numCourses];//[i][j] i为j的先决条件 i->jStack<...
代码如下: import java.util.ArrayList; import java.util.Arrays; import java.util.HashSet; import java.util.Iterator; import java.util.LinkedList; import java.util.List; import java.util.Queue; import java.util.Set; /* * 本质就是判 public class Solution { public boolean canFinish(int numCou...
1 classSolution{ 2 public: 3 vector<int>findOrder(intnumCourses,vector<vector<int>>&prerequisites) { 4 5 } 6 }; 您必须登录后才能提交解答! © 2025 领扣网络(上海)有限公司版权所有 沪公网安备 31011502007040号 沪ICP备17051546号
Can you solve this real interview question? Course Schedule IV - There are a total of numCourses courses you have to take, labeled from 0 to numCourses - 1. You are given an array prerequisites where prerequisites[i] = [ai, bi] indicates that you must ta
【Leetcode】Course Schedule II https://leetcode.com/problems/course-schedule-ii/ 题目: There are a total of n courses you have to take, labeled from 0 to n - 1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as...
[LeetCode]CourseSchedule书影博客[LeetCode]CourseSchedule 书影博客 题目描述: There are a total of n courses you have to take, labeled from 0 to n - 1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0...
class Solution { class Node { int in; int value; List<Node> next; public Node(int value) { in = 0; this.value = value; next = new ArrayList<>(); } } public int[] findOrder(int numCourses, int[][] prerequisites) { Map<Integer, Node> nodeMap = new HashMap<>(); for(int ...
Java: classSolution{publicintscheduleCourse(int[][]courses){intday=0;Arrays.sort(courses,(a,b)->(a[1]-b[1]));Queue<Integer>queue=newPriorityQueue<>();for(int[]course:courses){day+=course[0];queue.add(-course[0]);if(day>course[1])day+=queue.poll();}returnqueue.size();}} ...
LeetCode 207. Course Schedule This question is actually asking how to check whether a graph has a cycle: 1. Put all nodes and it's next node into a hashmap. e.g 1 -> [2,3] 2. For each node, perform DFS, recursively check if there's a cycle. Create a state array, 0 = not...