There are a total of 2 courses to take. To take course 1 you should have finished course 0. So it is possible. 2, [[1,0],[0,1]] There are a total of 2 courses to take. To take course 1 you should have finished course 0, and to take course 0 you should also have finished...
} Stack<Integer> out[] =newStack[numCourses];//所有的边for(inti = 0; i < numCourses; i++) { out[i]=newStack<Integer>(); }int[] in =newint[numCourses];//统计入度的数组for(inti = 0; i < prerequisites.length; i++) { out[prerequisites[i][0]].push(prerequisites[i][1]); ...
for(int i=0;i<prerequisites.length;i++) { int to=prerequisites[i][0]; int from=prerequisites[i][1]; list.get(from).add(to); preCount[to]++; } //使用队列来拓扑排序 Queue<Integer> queue=new LinkedList<Integer>(); for(int i=0;i<numCourses;i++) { if(preCount[i]==0) queue...
Can you solve this real interview question? Course Schedule IV - There are a total of numCourses courses you have to take, labeled from 0 to numCourses - 1. You are given an array prerequisites where prerequisites[i] = [ai, bi] indicates that you must ta
题目地址:https://leetcode.com/problems/course-schedule/description/ 题目描述: There are a total of n courses you have to take, labeled from0ton-1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair:[0,1] ...
[LeetCode]CourseSchedule 书影博客 题目描述: There are a total of n courses you have to take, labeled from 0 to n - 1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1] Given the total number ...
现在你总共有numCourses门课需要选,记为0到numCourses - 1。给你一个数组prerequisites,其中prerequisites[i] = [ai, bi],表示在选修课程ai前必须先选修bi。 例如,想要学习课程0,你需要先完成课程1,我们用一个匹配来表示:[0,1]。 返回你为了学完所有课程所安排的学习顺序。可能会有多个正确的顺序,你只要返回...
for(int i = 0; i < numCourses; ++i) { int tmp = 0; while (indegree[tmp] != 0 && tmp < numCourses) ++tmp; if(tmp == numCourses) break; indegree[tmp] = -1; res.push_back(tmp); for(int j = 0; j < graph[tmp].size(); ++j) { ...
207. Course Schedule 题目描述(中等难度) 给定n组先修课的关系,[m,n]代表在上m这门课之前必须先上n这门课。输出能否成功上完所有课。 解法一 把所有的关系可以看做图的边,所有的边构成了一个有向图。 对于[ [1,3],[1,4], [2,4],[3,5],...
value = value; next = new ArrayList<>(); } } public int[] findOrder(int numCourses, int[][] prerequisites) { Map<Integer, Node> nodeMap = new HashMap<>(); for(int i = 0 ; i < numCourses; i++) { nodeMap.put(i, new Node(i)); } for(int[] edge: prerequisites) { int...