例如,想要学习课程0,你需要先完成课程1,我们用一个匹配来表示:[0,1]。 返回你为了学完所有课程所安排的学习顺序。可能会有多个正确的顺序,你只要返回任意一种就可以了。如果不可能完成所有课程,返回一个空数组。 示例1: 输入:numCourses = 2, prerequisites = [[1,0]]输出:[0,1]解释:总共有 2 门课程。
LeetCode - Course Schedule II There are a total of n courses you have to take labelled from 0 to n - 1. Some courses may have prerequisites, for example, if prerequisites[i] = [ai, bi] this means you must take the course bi before the course ai. Given the total number of courses...
[LeetCode] Course Schedule II There are a total of n courses you have to take, labeled from0ton - 1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair:[0,1] Given the total number of courses and a lis...
Leetcode】210.course-schedule-ii题目地址 https://leetcode.com/problems/course-schedule-ii/ 题目大意 https://leetcode-cn.com/problems/course-schedule-ii 解题思路 有向图的拓扑排序,采用BFS解决。对每组数字,如[1,0], 实际可表示为一条从结点0指向结点1的边,对记录下每个结点的入度数。循环遍历每个...
There may be multiple correct orders, you just need to return one of them. If it is impossible to finish all courses, return an empty array. 使用拓扑排序即可,代码如下: class Solution { public: vector<int> findOrder(int numCourses, vector<vector<int>>& prerequisites) { ...
【Leetcode】Course Schedule II https://leetcode.com/problems/course-schedule-ii/ 题目: There are a total of n courses you have to take, labeled from 0 to n - 1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as...
210. Course Schedule II # 题目 # There are a total of n courses you have to take, labeled from 0 to n-1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1] Given the to
[leetcode] 210. Course Schedule II Description There are a total of n courses you have to take, labeled from 0 to n-1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1]...
参考上题,Java for LeetCode 207 Course Schedule【Medium】 修改下代码即可,JAVA实现如下: publicint[]findOrder(intnumCourses,int[][]prerequisites){ int[]res=newint[numCourses]; List<Set<Integer>>posts=newArrayList<Set<Integer>>(); for(inti=0;i<numCourses;i++) ...
我在leetcode 210上成功AC的代码,为何在linCode 616上卡在了10001的case,报错temsig=11,是因为占用空间太多? class Solution: # @param {int} numCourses a total of n courses # @param {int[][]} prerequisites a list of prerequisite pairs # @return {int[]} the course order neighbors = None vis...