= prerequisite[i][1] The prerequisites graph has no cycles. The prerequisites graph has no repeated edges.1 <= queries.length <= 10^4queries[i][0] != queries[i][1] BFS TLE: classSolution {publicList<Boolean> checkIfPrerequisite(intn,int[][] prerequisites,int[][] queries) {//initiat...
Can you solve this real interview question? Course Schedule IV - There are a total of numCourses courses you have to take, labeled from 0 to numCourses - 1. You are given an array prerequisites where prerequisites[i] = [ai, bi] indicates that you must ta
题目地址:https://leetcode-cn.com/problems/course-schedule-iv/ 题目描述 你总共需要上n门课,课程编号依次为0到n-1。 有的课会有直接的先修课程,比如如果想上课程0,你必须先上课程1,那么会以[1,0]数对的形式给出先修课程数对。 给你课程总数n和一个直接先修课程数对列表prerequisite和一个查询对列表queri...
1classSolution {2publicList<Boolean> checkIfPrerequisite(intn,int[][] prerequisites,int[][] queries) {3int[] indegree =newint[n];4HashMap<Integer, Set<Integer>> adj =newHashMap<>();5HashMap<Integer, Set<Integer>> preMap =newHashMap<>();6for(inti = 0; i < n; i++) {7preMa...
题目地址:https://leetcode.com/problems/course-schedule/description/ 题目描述: There are a total of n courses you have to take, labeled from0ton-1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair:[0,1] ...
[LeetCode]CourseSchedule书影博客[LeetCode]CourseSchedule 书影博客 题目描述: There are a total of n courses you have to take, labeled from 0 to n - 1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0...
贡献者:LeetCode 相关标签 深度优先搜索广度优先搜索图拓扑排序 相似题目 课程表火星词典最小高度树序列重建课程表 III并行课程从给定原材料中找到所有可以做出的菜给定条件下构造矩阵通过移动项目到空白区域来排序数组 1 classSolution{ 2 public: 3 vector<int>findOrder(intnumCourses,vector<vector<int>>&prerequisit...
class Solution { class Node { int in; int value; List<Node> next; public Node(int value) { in = 0; this.value = value; next = new ArrayList<>(); } } public int[] findOrder(int numCourses, int[][] prerequisites) { Map<Integer, Node> nodeMap = new HashMap<>(); for(int ...
LeetCode 207. Course Schedule This question is actually asking how to check whether a graph has a cycle: 1. Put all nodes and it's next node into a hashmap. e.g 1 -> [2,3] 2. For each node, perform DFS, recursively check if there's a cycle. Create a state array, 0 = not...
class Solution{public:intscheduleCourse(vector<vector<int>>&courses){sort(courses.begin(),courses.end(),[](constauto&a,constauto&b){returna.back()<b.back();});intday=0;priority_queue<int>pq;for(auto&course:courses){day+=course.front();pq.emplace(course.front());if(day>course.back...