Can you solve this real interview question? Count Number of Nice Subarrays - Given an array of integers nums and an integer k. A continuous subarray is called nice if there are k odd numbers on it. Return the number of nice sub-arrays. Example 1:
Given an integer arraynumsand an integerk, returnthe number ofgoodsubarrays ofnums. A subarrayarrisgoodif there areat leastkpairs of indices(i, j)such thati < jandarr[i] == arr[j]. Asubarrayis a contiguousnon-emptysequence of elements within an array. Example 1: Input:nums = [1,1...
Given an array of integers nums and an integer k. A continuous subarray is called nice if there are k odd numbers on it. Return the number of nice sub-arrays. Example 1: Input: nums = [1,1,2,1,1], k = 3 Output: 2 Explanation: The only sub-arrays with 3 odd numbers are [1...
Given an array of integersnumsand an integerk. Asubarray is called nice if there arekodd numbers on it. Return the number of nice sub-arrays. Example 1: Input: nums = [1,1,2,1,1], k = 3 Output: 2 Explanation: The only sub-arrays with 3 odd numbers are [1,1,2,1] and [1...
A set of practice note, solution, complexity analysis and test bench to leetcode problem set - leetcode/CountSubArrayFixBound.drawio at b58bcceb0ea27d0756ad72fb6a64b3b547fae221 · brianchiang-tw/leetcode
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public int numSubarraysWithSum(int[] nums, int goal) { // 滑动窗口(容斥原理,同1248) // 和为goal的连续子数组的数量。// 「和恰好为goal的子数组数量」=「和最多为goal的子数组数量」-「和最多为goal-1的子数组数量」 return atMost(nums, goal) - atMost(nums, goal - 1); }...
Leetcode 1248 问题描述 Given anarrayofintegers numsandanintegerk. A subarrayiscallednice if therearek odd numbersonit.Returnthe numberofnice sub-arrays. 例子 Example 1:Input:nums=[1,1,2,1,1],k=3Output:2Explanation:Theonlysub-arrayswith3oddnumbersare[1,1,2,1]and[1,2,1,1].Example 2...
Given an array of integersnumsand an integerk. A continuous subarray is called nice if there arekodd numbers on it. Returnthe number of nice sub-arrays. Example 1: Input:nums = [1,1,2,1,1], k =3Output:2Explanation:The onlysub-arrayswith3odd numbers are [1,1,2,1]and[1,2,1,...
Code you used for Submit/Run operation class Solution { public: int numberOfSubarrays(vector<int>& nums, int k) { int n = nums.size(); int cnt = 0; vector <int> odd1 (n); odd1[0] = (nums[0]%2!=0); for(int i=0; i<n; i++){ if(nums[i]%2==0){ odd1[i] = ...