so that when xor'ed with E, the resultant's leftmost bit will be smaller than K's leftmost bit. So, from root of trie, you check if you can go to a node with 0. If you can't, it means no pair exists for E.
A set of practice note, solution, complexity analysis and test bench to leetcode problem set - leetcode/CountSubArrayFixBound.drawio at b58bcceb0ea27d0756ad72fb6a64b3b547fae221 · brianchiang-tw/leetcode
/*C program to count total number of elementsdivisible by a specific number in an array*/#include <stdio.h>#define MAX 5intmain() {intarr[MAX]={0};inti;intb=10;intcount=0; printf("Enter array elements:\n");for(i=0; i<MAX; i++) { scanf("%d",&arr[i]);if(a...
1402-count-square-submatrices-with-all-ones 1408-find-the-smallest-divisor-given-a-threshold 1415-students-and-examinations 1431-all-ancestors-of-a-node-in-a-directed-acyclic-graph 1433-encrypt-and-decrypt-strings 1435-xor-queries-of-a-subarray 1447-jump-game-iv 1452-restaurant-growth 1456-find...