To the right of 5 there are 2 smaller elements (2 and 1). To the right of 2 there is only 1 smaller element (1). To the right of 6 there is 1 smaller element (1). To the right of 1 there is 0 smaller element. R
please clarify > >= whether add = can cause largely difference in many situations in this code if you not write l<=r ,not =,will cause a lot of problem #include<stdio.h>#include<iostream>#include<vector>#include<algorithm>#include<stack>#include<string>#include<memory>#include<memory.h>...
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solution3: binary search; code 参考 1.leetcode_1351. Count Negative Numbers in a Sorted Matrix; 完 各美其美,美美与共,不和他人作比较,不对他人有期待,不批判他人,不钻牛角尖。 心正意诚,做自己该做的事情,做自己喜欢做的事情,安静做一枚有思想的技术媛。
To the right of 5 there are 2 smaller elements (2 and 1). To the right of 2 there is only 1 smaller element (1). To the right of 6 there is 1 smaller element (1). To the right of 1 there is 0 smaller element. Approach #1: C++. [Fenwick Tree / Binary Indexed Tree] 1 ...
{intn =arr.length;//Sort the array elements in non-decreasing orderArrays.sort(arr);//Initialize count of trianglesintcount = 0;//Fix the first element. We need to run till n-3 as//the other two elements are selected from arr[i+1...n-1]for(inti = 0; i < n-2; ++i) ...