Given a sorted array arr[] and a number x, write a function that counts the occurrences of x in arr[]. Expected time complexity is O(Logn) Examples: Input: arr[] = {1, 1, 2, 2, 2, 2, 3,}, x = 2 Output: 4 // x (or 2) occurs 4 times in arr[] Input: arr[] = {...
please clarify > >= whether add = can cause largely difference in many situations in this code if you not write l<=r ,not =,will cause a lot of problem #include<stdio.h>#include<iostream>#include<vector>#include<algorithm>#include<stack>#include<string>#include<memory>#include<memory.h>...
A set of practice note, solution, complexity analysis and test bench to leetcode problem set - leetcode/CountSubArrayFixBound.drawio at b58bcceb0ea27d0756ad72fb6a64b3b547fae221 · brianchiang-tw/leetcode
My Solutions to Leetcode problems. All solutions support C++ language, some support Java and Python. Multiple solutions will be given by most problems. Enjoy:) 我的Leetcode解答。所有的问题都支持C++语言,一部分问题支持Java语言。近乎所有问题都会提供多个算
solution3: binary search; code 参考 1.leetcode_1351. Count Negative Numbers in a Sorted Matrix; 完 各美其美,美美与共,不和他人作比较,不对他人有期待,不批判他人,不钻牛角尖。 心正意诚,做自己该做的事情,做自己喜欢做的事情,安静做一枚有思想的技术媛。