Recall the problem of finding the number of inversions. As in the course, we are given a sequence of numbers and we define an inversion to be a pair such that We motivated the problem of counting inversions as a good measure of how different two orderings are. However, one might feel ...
你的任务是：构建一个长度为 n 的整数数组 perm，它是从 [0, 1, 2, ..., n-1] 中的所有元素的某种排列 讲
A set of practice note, solution, complexity analysis and test bench to leetcode problem set - leetcode/CountSubArrayFixBound.drawio at b58bcceb0ea27d0756ad72fb6a64b3b547fae221 · brianchiang-tw/leetcode
returns the number of inversions in the array.*/int_mergeSort(intarr[],inttemp[],intleft,intright) { //分-递归intmid, inv_count =0;if(right >left) {/*Divide the array into two parts and call _mergeSortAndCountInv() for each of the parts*/mid= (right + left) /2;/*Inversion ...