Can you solve this real interview question? Global and Local Inversions - You are given an integer array nums of length n which represents a permutation of all the integers in the range [0, n - 1]. The number of global inversions is the number of the di
The number of local inversions is the number ofiwith0 <= i < NandA[i] > A[i+1]. Returntrueif and only if the number of global inversions is equal to the number of local inversions. Example 1: Input: A = [1,0,2] Output: true Explanation: There is 1 global inversion, and 1 ...
The number of local inversions is the number of i with 0<= i< N and A[i]>A[i+1]. Return true if and only if the number of global inversions is equal to the number of local inversions. Example 1:Input: A = [1,0,2] Output: true Explanation: There is 1 global inversion, and...
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https://leetcode.com/problems/global-and-local-inversions/ 题目描述 We have some permutation A of [0, 1, ..., N - 1], where N is the length of A. ...
Reference: https://leetcode.com/problems/global-and-local-inversions/discuss/113656/My-3-lines-C%2B%2B-Solution 永远渴望,大智若愚(stay hungry, stay foolish)
boolisIdealPermutation(vector<int>&A) {for(inti =0; i < A.size(); ++i)if(abs(A[i] - i) >1)returnfalse;returntrue; } 参考: https://leetcode.com/problems/global-and-local-inversions/discuss/113644/Easy-and-Concise-Solution-C++JavaPython...
[leetcode]775. Global and Local Inversions 核心思想: 1.局部倒置属于全局倒置,要想相等必须都是局部倒置 2.局部倒置前后交换后会回到正确位置 publicbooleanisIdealPermutation(int[] A) {/*局部倒置属于全局倒置,所以要想两者相等,全局倒置必须都是局部倒置...
The number of local inversions is the number of i with 0 <= i < N and A[i] > A[i+1]. Return true if and only if the number of global inversions is equal to the number of local inversions. Example 1: Input: A = [1,0,2] ...
The number of local inversions is the number ofiwith0 <= i < NandA[i] > A[i+1]. Returntrueif and only if the number of global inversions is equal to the number of local inversions. Example 1: Input: A = [1,0,2] Output: true ...