answer means-- number of elements to its right such that they are greater than this element → Reply X-OR 11 months ago, # | 0 I guess you are trying to find count of inversions in array which is if i < j and a[i] > a[j] This can be done using merge sort along with...
Task 1: Given q(≤100000)q(≤100000) queries and L,R,(pair p)L,R,(pair p), output the number of pairs < p in the range [L,R][L,R]. Task 2: Count the number of inversions in it. I can do inversions += query(i+1,n,p[i]) (if answer to Task 1 is available). Task...
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in a sorted array we have no inversions because every element is properly placed. but in an unsorted array, the number of inversions tells us how “disordered” the array is. the more inversions, the more steps we need to take to sort the array by swapping adjacent elements. 2.1. example...
2a. accumulate the number of inversions to counter variable num_inversions. 2b. remove A[1] from array A and also from its corresponding position in array B rerun from step 2 until there are no more elements in A. Here’s an example run of this algorithm. Original array A = (6, 9,...
Thus, without space optimization, calculating rr has a complexity of O(nk)O(nk); Calculating the array bb for each group takes O(Snkw)O(Snkw), resulting in a total complexity of O(n2kw)O(n2kw). Since S≥wS≥w, the time complexity is O(n2kw)O(n2kw), and the space complexity ...
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(n)If we create a segment tree that stores values such as the number of prefixes and suffixes with an even and odd number of inversions and the number of substrings with an even and odd number of inversions that do not contain the first or last element, then for the given ...