Let A[0...n - 1] be an array of n distinct positive integers. If i < j and A[i] > A[j] then the pair (i, j) is called an inversion of A. Given n and an array A your task is to find the number of inversions of A. Input The first line contains t, the number of te...
I'm trying to come up with a recursive solution for this problem but I haven't been able to so far. Any advice/pointers here? I tried 0-1 knapsack style but there is an issue with backtracking the array.+3 aakarshmadhavan 7 years ago 1 ...
6 is in the 4th position of array B, thus there are 3 inversions. We know this because 6 was in the first position in array A, thus any lower value element that subsequently appears in array A would have an index of j > i (since i in this case is 1). 2.b: Remove A[1] fro...
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. Give an algorithm to count the number of significant inversions between two orderings. The array contains N elements . All elements are in the range from 1 to 1,000,000,000. Input The first line contains one integer , indicating the size of the array. The second line contains ...
the array is. the more inversions, the more steps we need to take to sort the array by swapping adjacent elements. 2.1. example let’s look at a simple example. suppose we have an array: int[] array = {3, 1, 2}; in this array, there are two inversions: (3, 1) because 3 ...
Given an array of pairs p[]p[] of length n(≤100000)n(≤100000) I want to do the following: Task 1: Given q(≤100000)q(≤100000) queries and L,R,(pair p)L,R,(pair p), output the number of pairs < p in the range [L,R][L,R]. Task 2: Count the number of inversions...
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When k=2k=2, the problem simplifies to counting inversions, solvable directly using a Fenwick Tree. For k=3k=3, one can consider a Divide and Conquer (D&C) approach, achieving a complexity of O(nlog2n)O(nlog2n), which is excellent. Alternatively, a K-D Tree approach achieves O...