Given a binary treeroot, a nodeXin the tree is named good if in the path from root toXthere are no nodes with a valuegreater thanX. Return the number of good nodes in the binary tree. Example 1: Input: root = [3,1,4,3,null,1,5] Output: 4 Explanation: Nodes in blue are good...
https://leetcode.com/problems/count-complete-tree-nodes/discuss/61958/Concise-Java-solutions-O(log(n)2) https://leetcode.com/problems/count-complete-tree-nodes/discuss/61953/Easy-short-c%2B%2B-recursive-solution https://leetcode.com/problems/count-complete-tree-nodes/discuss/61948/Accepted-Easy...
what do you need to know about the complete binary tree is, let’s assume the root is depth of 0 and the maximum depth is d, so the total number of nodes besides the leaf level will be 2^ (d) - 1, and the number of leaves is in the range of (1, 2^d) and all we need ...
Given the root of a binary tree, return the number of nodes where the value of the node is equal to the sum of the values of its descendants. A descendant of a node x is any node that is on the path from node x to some leaf node. The sum is considered to be 0 if the node ...
1. 找到tree 的height O(lg h) 2. 建一个helper function来看index 是否exist, O (lg h) 3. 找last index that node exists. 4. 然后将最后一level的nodes + 之前所有node的数目,最后返回结果即可 Code: #Definition for a binary tree node.#class TreeNode:#def __init__(self, val=0, left=Non...
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Given a binary tree, count the number of uni-value subtrees. A Uni-value subtree means all nodes of the subtree have the same value. Example Example1 代码语言:javascript 代码运行次数:0 运行 AI代码解释 Input: root = {5,1,5,5,5,#,5} Output: 4 Explanation: 5 / \ 1 5 / \ \ 5...
828. Count Unique Characters of All Substrings of a Given String # 题目 # Let’s define a function countUniqueChars(s) that returns the number of unique characters on s, for example if s = "LEETCODE" then "L", "T","C","O","D" are the unique characters
In a complete binary tree every level, except possibly the last, is completely filled, and all nodes in the last level are as far left as possible. It can have between 1 and 2h nodes inclusive at the last level h. Solution: 1. 1st naive method. ...