Given a binary treeroot, a nodeXin the tree is named good if in the path from root toXthere are no nodes with a valuegreater thanX. Return the number of good nodes in the binary tree. Example 1: Input: root = [3,1,4,3,null,1,5] Output: 4 Explanation: Nodes in blue are good...
[leetcode] 1448. Count Good Nodes in Binary Tree Description Given a binary tree root, a node X in the tree is named good if in the path from root to X there are no nodes with a value greater than X. Return the number of good nodes in the binary tre......
http://www.programcreek.com/2014/06/leetcode-count-complete-tree-nodes-java/ 1defgetLeftMostHeight(root):2depthLeft =03while(root):4root =root.left5depthLeft += 16returndepthLeft789defgetRightMostHeight(root):10depthRight =011while(root):12root =root.right13depthRight += 114returndepthRight...
Given a complete binary tree, count the number of nodes. In a complete binary tree every level, except possibly the last, is completely filled, and all nodes in the last level are as far left as possible. It can have between 1 and 2h nodes inclusive at the last level h. which means ...
在LeetCode 1973题中,DFS算法的时间复杂度是多少? 文章目录 1. 题目 2. 解题 1. 题目 Given the root of a binary tree, return the number of nodes where the value of the node is equal to the sum of the values of its descendants. A descendant of a node x is any node that is on the...
1. 找到tree 的height O(lg h) 2. 建一个helper function来看index 是否exist, O (lg h) 3. 找last index that node exists. 4. 然后将最后一level的nodes + 之前所有node的数目,最后返回结果即可 Code: #Definition for a binary tree node.#class TreeNode:#def __init__(self, val=0, left=Non...
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In a complete binary tree every level, except possibly the last, is completely filled, and all nodes in the last level are as far left as possible. It can have between 1 and 2h nodes inclusive at the last level h. 链接:http://leetcode.com/problems/count-complete-tree-nodes/ ...