= [(sint + cost)/√2] / [(cost - sint)/√2]= (sint cosπ/4 + cost sinπ/4) / (cost cosπ/4 - sint sinπ/4)= sin(t+π/4) / cos(t+π/4)= tan(t+π/4)
百度试题 结果1 题目(cost+sint)/(cost-sint) 【题目】化简 相关知识点: 试题来源: 解析反馈 收藏
cost（1-cost）-sint.sint =cost - [ (cost)^2 + (sint)^2 ]=cost -1
因为这是一个关于t的方程，而不是一个恒等式。所以只能先化简，再求t 详情如下:因为 sin⁴t+cos⁴t ＝sin⁴t+2sin²tcos²t+cos⁴t -2sin²tcos²t ＝(sin²t+cos²t)-2sin²tcos²t ＝1-(1/2)sin²2t ...
化简:cost4sint2+sint4cost2 相关知识点: 试题来源: 解析 解: cos (t^4)sin (t^2)+sin (t^4)cos (t^2) =cos (t^2)sin (t^2)(cos (t^2)+sin (t^2)) =cos (t^2)sin (t^2) = 1/ 4* 2cos tsin t* 2cos tsin t = 1/ 4((sin (2t)))^2...
计算:1.(√3-1)^0+(1/8)^(-2/3)+2lg5+lg2/5-2log_20. 2.化简f(u)=(sint)/(cost)dt=sin(ωt⋅sinπ/(
解析 sint^4+cost^4=(sint^2+cost^2)^2-2sint^2cost^2=1-0.5sin2t^2=1-0.25(1-cos4t)=0.25cos4t+0.75 结果一 题目 sint^4+cost^4的化简 答案 sint^4+cost^4=(sint^2+cost^2)^2-2sint^2cost^2=1-0.5sin2t^2=1-0.25(1-cos4t)=0.25cos4t+0.75相关推荐 1sint^4+cost^4的化简 ...
解cost^4sint^2+sint^4cost^2 =cost^2sint^2（cost^2+sint^2）=cost^2sint^2 =1/4×2costsint×2costsint =1/4sin2t×sin2t =1/4（sin2t）^2
sin2A=2sinAcosA √cost4 sint4=√1/2sin8=√2/2√sin8