cos alpha+cos beta-cos(alpha+beta)=(3)/(2) then show that alpha=beta=(pi)/(3) View Solution Let alpha=(pi)/(5) and A,=[[cos alpha,sin alpha-sin alpha,cos alpha]] then B=A^(4)-A^(3)+A^(2)-A is View Solution Ifα=π3, prove thatcosα⋅cos2α⋅cos3α⋅cos4...
यदि alpha + beta = 60^@ तो सिद्ध करें की cos^2 alpha+cos^2 beta - cos alpha * cos beta = 3/4
https://www.quora.com/Why-is-sin-alpha-sin-beta-frac-1-2-cos-alpha-beta-cos-alpha+-beta To show why, our goal will be to manipulate the right side of the identity: sin α sin β = (1/2)[cos(α ...
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所以;0<{}\alpha +\beta < {} \pi ,又\cos \left( \alpha +\beta \right)=\frac{1}{7}, 所以;\sin \left( \alpha +\beta \right)=\frac{4\sqrt{3}}{7}, 则\cos \beta =\cos \left[ \left( \alpha +\beta \right)-\alpha \right] ~~~=\cos \left( \alpha +\beta \right)...
【解析】证明: 【解析】证明: \$\because 2 \cos ( \alpha - \beta ) \cos \alpha - \cos [ \alpha + ( \alpha - \beta ) ]\$ \$= 2 \cos ( \alpha - \beta ) \cos \alpha - [ \cos ( \alpha - \beta ) \cos ( \alpha - \sin ( \alpha - \beta ) \sin \alpha...
结果1 题目 已知\sin (\alpha - \beta )=2\cos (\alpha \beta ), \tan (\alpha - \beta )=1\div 2,则\tan \alpha - \tan \beta = () A. 4\div 7\ \ B. 7\div 4\ \ C. 7\div 6\ \ D. 4\div 5\ \ 相关知识点: 试题来源: 解析 D 反馈 收藏 ...
\$\sin ( 2 \alpha + \beta ) = \sin \beta + 2 \sin \alpha \cos ( \alpha + \beta )\$ 证明:。 相关知识点: 试题来源: 解析 【规范解答】2。因为 _ \$= \sin [ ( \alpha + \beta ) + \alpha ] - 2 \sin \alpha \cos ( \alpha + \beta )\$ \$= \sin ( \alpha...
已知\(\tan(\alpha) = 2\),\(\cos(\beta) = \frac{3}{5}\),求\(\sin(\alpha \beta)\)的值。 答案 C 解析 null 本题来源 题目:已知\(\tan(\alpha) = 2\),\(\cos(\beta) = \frac{3}{5}\),求\(\sin(\alpha \beta)\)的值。 来源: 山东会考数学试题及答案 收藏...
所以1+2(\sin\beta )^2=4(\ sin\alpha )^2 2\cos2\alpha =2[1-2(\sin\alpha)^2]=2-4(\sin\alpha)^2=2-[1+2(\sin\beta )^2]=1-2(\sin\beta )^2=\cos2\beta 本题主要利用三角函数的性质进行求证。反馈 收藏