第一步:先复制原始链表中的节点,用next指针链接起来,在复制节点时放入map中 第二步:设置每个节点的random指针 空间复杂度为O(n),时间复杂度为O(n) Accepted Code 1publicRandomListNode copyRandomList(RandomListNode head) {2//Note: The Solution object is instantiated only once and is reused by each tes...
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 题意:普通的链表中给定一个随机指针,该指针可以为空,也可以指向链表中任意节点。要求对该链表深拷贝。 思路: 与普通的链表拷贝不...
#include<iostream>#include<new>usingnamespacestd;//Definition for singly-linked list with a random pointer.structRandomListNode {intlabel; RandomListNode*next, *random; RandomListNode(intx) : label(x), next(NULL), random(NULL) {} };classSolution {public: RandomListNode*copyRandomList(RandomList...
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 栈迭代 复杂度 时间O(N) 空间 O(N) 如果不算新链表的空间则是O(1) 思路 由于随机指针有可能产生环路,我们不能直接沿着随机指...
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return adeep copyof the list. The Linked List is represented in the input/output as a list ofnnodes. Each node is represented as a pair of[val, random...
[前端]-[刷题]-leetcode 138 copy-list-with-random-pointer, 视频播放量 15、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 rhythm022, 作者简介 ,相关视频:[前端]-[刷题]-leetcode 1721 swapping-nodes-in-a-linked-list,[前端]-[刷题]-leetcod
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. Solution: publicRandomListNodecopyRandomList(RandomListNodehead){if(head==null)returnnull;RandomListNodeiter=head;while(iter!=nul...
题目: 138. Copy List with Random Pointer A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the ...
Copy List with Random Pointer A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 首先搞清楚什么是浅拷贝和深拷贝: 浅拷贝,把一个变量中的数据地址直接给另一个变量,删除其中任何一...
Can you solve this real interview question? Copy List with Random Pointer - A linked list of length n is given such that each node contains an additional random pointer, which could point to any node in the list, or null. Construct a deep copy [https://