要求返回这个链表的深拷贝。 A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return adeep copyof the list. 示例: Copy 输入: {"$id":"1","next":{"$id":"2","next":null,"random":{"$ref":"2"},...
并把新旧pointer存在HashMap中。 第二遍,遍历旧表,复制random的值,因为第一遍已经把链表复制好了并且也存在HashMap里了,所以只需从HashMap中,把当前旧的node.random作为key值,得到新的value的值,并把其赋给新node.random就好。 /*** Definition for singly-linked list with a random pointer. * class Random...
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 栈迭代 复杂度 时间O(N) 空间 O(N) 如果不算新链表的空间则是O(1) 思路 由于随机指针有可能产生环路,我们不能直接沿着随机指...
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 随机链表的节点数据结构 structRandomListNode {intlabel; RandomListNode*next, *random; RandomListNode(intx) : label(x), next(...
leetcode 138. Copy List with Random Pointer 链表复制 + HashMap,Alinkedlistisgivensuchthateachnodecontainsanadditionalrandompointerwhichcouldpointtoanynodeinthelistornull.Returnadeepcopyofthelist.本题题意就是复制链表,注意使用HashMap等结构保存相关信息,
Can you solve this real interview question? Copy List with Random Pointer - A linked list of length n is given such that each node contains an additional random pointer, which could point to any node in the list, or null. Construct a deep copy [https://
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给你一个长度为n的链表,每个节点包含一个额外增加的随机指针random,该指针可以指向链表中的任何节点或空节点。 构造这个链表的深拷贝。 深拷贝应该正好由n个全新节点组成,其中每个新节点的值都设为其对应的原节点的值。新节点的next指针和random指针也都应指向复制链表中的新节点,并使原链表和复制链表中的这些指针...
题目: 138. Copy List with Random Pointer A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the ...
A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. Solution: publicRandomListNodecopyRandomList(RandomListNodehead){if(head==null)returnnull;RandomListNodeiter=head;while(iter!=nul...