The order is inorder traversal. Use stack to help inorder traversal. When root is not null, push it into stack and move to its left child. When root is null, stack is not empty, pop the top and append it to current node's right. Then root = top.right. When root is null, stack...
* Source : https://oj.leetcode.com/problems/convert-sorted-array-to-binary-search-tree/ * * Given an array where elements are sorted in ascending order, convert it to a height balanced BST. * */publicclassConvertSortedArray{/** * 把一个已排序的数组转化我一颗高度平衡二叉搜索树,即AVL树,...
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. Example: AI检测代...
The idea is to traverse the binary search tree in aninorder fashionand enqueue all encountered keys. Then traverse the tree in apreorder fashionand for each encountered node, dequeue a key and assign it to the node. Following is the implementation of the above algorithm in C++, Java, and ...
pre=None slow=fast=head whilefastandfast.next: pre=slow slow=slow.next fast=fast.next.next root=TreeNode(slow.val) ifpre: pre.next=None root.left=self.sortedListToBST(head) root.right=self.sortedListToBST(slow.next) returnroot
preorder(root->right); } // Recursive function to in-place convert the given binary tree // by traversing the tree in a postorder manner inttransform(Node*root) { // base case: empty tree if(root==nullptr){ return0; } // recursively convert the left and right subtree first before ...
There are three types of recursion, distinguished by the visiting order – preorder, postorder and inorder. In another word, we visit every node for three times. We may visit a node coming from its parent node (preorder), from its left child (inorder), or from its right child(postorder...
Convert Sorted List to Binary Search Tree 题目: Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 转换成平衡二叉树,刚看到题目直接想到了中序,想了会没解决,于是一口气看了三部钢铁侠,“小辣椒”完美!好吧看完电影查了一下平衡二叉树的定义...
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 链接:http://leetcode.com/problems/convert-sorted-list-to-binary-search-tree/ 题解: 值得思考的一道题。一开始的想法是跟convert sorted array to BST一样,用快慢指针找到中点,然后自顶向...
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees ofeverynode never differ by more than 1. ...