publicTreeNodebuildTree(int[]preorder,int[]inorder){returnbuildTreeHelper(preorder,0,preorder.length,inorder,0,inorder.length);}privateTreeNodebuildTreeHelper(int[]preorder,intp_start,intp_end,int[]inorder,inti_start,inti_end){// preorder 为空,直接返回 nullif(p_start==p_end){returnnull;...
node =newTreeNode(preorder[pstart]);if(pstart == pend)return;inti;for(i = istart; i <= iend; i++)if(inorder[i] == preorder[pstart])break;recursiveBuild(node -> left, preorder, pstart +1, pstart + i - istart, inorder, istart, i -1);recursiveBuild(node -> right, pre...
}privateTreeNode buildTree(int[] preorder,intpreLo,intpreHi,int[] inorder,intinLo,intinHi) {if(preLo > preHi || inLo >inHi)returnnull; TreeNode root=newTreeNode(preorder[preLo]);introotAtInorder = 0;for(inti = inLo; i <= inHi; i++) {if(inorder[i] == root.val) {//...
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { private int preStart=0; public TreeNode buildTree(int[] preorder, int[] inorder) { return helper(0...
public TreeNode buildTree(int[] preorder, int[] inorder) { if(preorder==null || inorder==null) return null; HashMap<Integer, Integer> map = new HashMap<Integer, Integer>(); for(int i=0;i<inorder.length;i++) { map.put(inorder[i],i); ...
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 翻译:给定树的前序和中序遍历,构造二叉树。 注意: 树中不存在重复项。 思路:首先,你应该知道 前序遍历:根节点,左子树,右子树; ...
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{public TreeNodebuildTree(int[]preorder,int[]inorder){if(preorder==null||preorder.length==0)returnnull;if(in...
题目: Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 根据前序遍历和中序遍历结果构造二叉树。 思路分析: 分析二叉树前序遍历和中序遍历的结果我们发现: 二叉树前序遍历的第一个节点是根节点。 在中序遍历...
105. Construct Binary Tree from Preorder and Inorder Traversal——tree,程序员大本营,技术文章内容聚合第一站。
https://leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/description/ """ # Definition for a binary tree node. # class TreeNode(object): # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution(object): d...