1vector<int> inorderTraversal(TreeNode*root) {2vector<int>rVec;3stack<TreeNode *>st;4TreeNode *tree =root;5while(tree || !st.empty())6{7if(tree)8{9st.push(tree);10tree = tree->left;11}12else13{14tree =st.top();15rVec.push_back(tree->val);16st.pop();17tree = tree->...
但是inorder不简单啊,模仿递归记录调用处然后处理完当前函数回来,下午困得不行闷头试了好几次各种bug超Memory,看了我是歌手回来发现脑子清醒了 1vector<int> inorderTraversal(TreeNode *root) {2vector<int>nodes;3if(root == NULL)returnnodes;4stack<TreeNode *>tStack;5TreeNode * cur =root;6while(!tS...
usingSystem.Text; namespacebinarytree { #region 节点的定义 classnode { publicstringnodevalue; publicnode leftchild, rightchild; publicnode() { } publicnode(stringvalue) { nodevalue = value; } publicvoidassignchild(node left, node right)//设定左右孩子 { this.leftchild = left; this.rightchild...
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. For example, given preorder = [3,9,20,15,7] inorder = [9,3,15,20,7] Return the following binary tre...
order B. Traversing the forest corresponding to the binary tree in root-last order C. Traversing the forest corresponding to the binary tree in breadth-first order D. None of the above 答案：A 分析：正确答案:A 解析:前序遍历一个二叉树等价于按从树的根部、右子树、右子树查找顺序查找树。
INORDER AND PREORDER TRAVERSAL and DISPLAY OF EXISTING BINARY TREE IN COMPUTER MEMORYP K KumaresanJournal of Harmonized Research
15、课程:树(下).7、练习—Iterative Get和Iterative Add 2 -- 12:36 App 15、课程:树(下).13、练习—Construct Binary Tree from Preorder and Inorder Traversal 1 -- 9:07 App 15、课程:树(下).3、练习—Floor and Ceiling 11 -- 12:45 App 13、课程:哈希表(下).10、作业讲解 3 -- 6...
Memory Usage: 13.1 MB, less than 70.72% of Python3 online submissions for Binary Tree Inorder Traversal. None-trivial solution: NOTE: Maintain a stack, push root first, then every iteration, push left child first if existed. If a left child is searched, result.append(current_parent_node's...
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{publicTreeNodebuildTree(int[]preorder,int[]inorder){if(preorder==null||inorder==null||preorder.length!=inor...
Inorder 方法一:和Preorder方法一类似,直接做,但是需要一个计数器,第二次出栈的时候才可以输出。 classSolution {public: vector<int> inorderTraversal(TreeNode*root) { vector<int>res;if(root==NULL)returnres; unordered_map<TreeNode *,int> hash;//default value is 0;stack<TreeNode *>s({root})...