于是就看了solution。 需要使用一个定理: 代码语言:javascript 代码运行次数:0 publicbooleancheckSubarraySum(int[]nums,int k){Map<Integer,Integer>map=newHashMap<Integer,Integer>();map.put(0,-1);//为了处理nums=[0,0] k=-1这样的情况int sum=0;for(int i=0;i<nums.length;i++){sum+=nums[...
1classSolution {2func checkSubarraySum(_ nums: [Int], _ k: Int) ->Bool {3ifnums.count <2{returnfalse}4if(k ==0) {returnnums[0] ==0&& nums[1] ==0}5vardict =[Int:Int]()67varsum =08foriin0...nums.count-1{9sum +=nums[i]1011let r = sum %k12ifr ==0{1314if(i>=1...
这个题虽然是easy,但是是leetcode上标记为Google 的面试题。 解法一:预先排序,找到最左边和最右边与排序后的数组不一样的地方 T:O(nlogn) S: O(n) classSolution {publicintfindUnsortedSubarray(int[] nums) {int[] sorted =nums.clone(); Arrays.sort(sorted);intstart = 0;while(start <nums.length)...
Leetcode 523. Continuous Subarray Sum prefix sum classSolution(object):defcheckSubarraySum(self, nums, k):""":type nums: List[int] :type k: int :rtype: bool"""ifk ==0:returnany(nums[i - 1] == 0andnums[i] == 0foriinrange(1, len(nums))) book, s={0: 0}, 0fori, vin...
This problem has very detailed solution. So just check out the solution page. Method 1: Use monotone stack to record the leftmost and rightmost index. classSolution{publicintfindUnsortedSubarray(int[] nums){intN=nums.length; Stack<Integer> s =newStack<Integer>();intl=N, r =0; ...
LeetCode 581. Shortest Unsorted Continuous Subarray 原题链接在这里:https://leetcode.com/problems/shortest-unsorted-continuous-subarray/ 题目: Given an integer array, you need to find one continuous subarray that if you only sort this subarray in ascending order, then the whole array will be ...
LeetCode 581. Shortest Unsorted Continuous Subarray 原题链接在这里:https://leetcode.com/problems/shortest-unsorted-continuous-subarray/ 题目: Given an integer array, you need to find one continuous subarray that if you only sort this subarray in ascending order, then the whole array will be ...
1classSolution {2func findUnsortedSubarray(_ nums: [Int]) ->Int {3ifnums.count ==0{4return05}67varrightIndex : Int =08varmax : Int = nums[0]9forindexin1..<nums.count {10ifnums[index] >=max {11max =nums[index]12}else{13rightIndex =index14}15}1617varleftIndex : Int =018var...
In case there is no subarray satisfying the given condition return 0. Example 1: Input: nums = [8,2,4,7], limit = 4 Output: 2 Explanation: All subarrays are: [8] with maximum absolute diff |8-8| = 0 <= 4. [8,2] with maximum absolute diff |8-2| = 6 > 4. ...
链接:https://leetcode.cn/problems/longest-continuous-subarray-with-absolute-diff-less-than-or-equal-to-limit 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 找一个最长的子数组,他们之间的最大值和最小值不能大于limit。我提供三种思路。