@文心快码BaiduComate[error] continue statement not within a loop 文心快码BaiduComate 解释“continue语句不在循环内”的错误含义 “continue语句不在循环内”是一个编译时错误,它表明continue语句被错误地放置在了循环结构之外。continue语句的目的是跳过当前迭代中剩余的代码,直接进入下一次循环迭代。因此,它必须位于...
导致 编译器认为continue不在循环的内部 把分号删掉即可 while(scanf("%f", &score) == 1) 后面多了个分号，导致后面的continue没有在循环语句之中使用。continue语句不能方在if语句中，只能放到循环语句中while(scanf("%f", &score) == 1) 后面多了个分号！！！
continue这个语句只能在循环块中用，比如for while do while，不能用在分支语句，如if else等
So the thing is, why am I getting the (Continue statement not within a loop.) error? and if it is possible, how can i assign the (You have chosen) into a variable? because whenever I type in: charchosen [25]= You have chosen ...
Continue statement continue语句用于跳过迭代,但它并不像我预期的那样起作用。这是我的代码: int i = 0; do { if(i== 10)continue; printf("\n This is = %d",i); i++; } while (i<20); 我的理解是它会跳过 这是=10 其余部分将打印,但由于...
The syntaxerror: 'continue' not properly in loop occurs when you're trying to use the continue statement outside of a loop...
一、continue语句 只结束本次循环，而不是终止整个循环的执行。二、break语句 【1】则是结束整个循环...
PostgreSQL supports a “continue” statement that lets us skip the loop’s current iteration and proceed to the subsequent iteration.
tmp.c: Infunction‘func’: tmp.c:6:2: error: break statement not within loop or switch break;^ 我只翻译上面报错的两句: error: continue语句不在一个循环里 error: break语句不在一个循环或者选择(语句)里 可见,不能用break或者continue从函数里面跳转出来...
*/ continue; } /* This print statement would not execute for the * loop iteration where j ==4 because in that case * this statement would be skipped. */ printf("%d ", j); } return 0; } C Copy输出:0 1 2 3 5 6 7 8 C Copy输出中缺少值 4,为什么?当变量j的值为 4 时,...