解法二:排序 class Solution: ## 先排序,后逐一对比。NlogN--1 def containsDuplicate(self, nums: List[int]) -> bool: ## 补缺 if len(nums)<=1: return False nums.sort() # Timsort in Python, nlogn for i in range(len(nums)): if nums[i]==nums[i-1]: return True return False ...
【LeetCode】Contains Duplicate II 解题小结 题目:Given an array of integers and an integerk, find out whether there are two distinct indicesiandjin the array such that nums[i] = nums[j] and the difference betweeniandjis at mostk. 题目意思就是判断在一个数组中是否存在两个相同的元素,他们之...
(leetcode题解)Contains Duplicate Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 题意给定一个数组,查找数组是否...
LeetCode - Find the Duplicate Number 题目Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number,...猜你喜欢为什么要学集合源码? 1.学习集合源码,能...
func containsDuplicate(nums []int) bool { // 将 nums 转成集合 numSet := make(map[int]bool) for _, num := range nums { numSet[num] = true } // 集合的长度不等于 nums 的长度时,才含有重复数字 return len(numSet) != len(nums) } 题目链接: Contains Duplicate: leetcode.com/proble...
class Solution(object): def containsDuplicate(self, nums): return len(set(nums)) != len(nums) if len(nums) != 0 else False 1. 2. 3.
【Leetcode】Contains Duplicate 题目链接:https://leetcode.com/problems/contains-duplicate/ 题目: Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element...
Leetcode 220 Contains Duplicate III如何解决 简介 220存在重复元素。给定一个整数数组，判断数组中是否有两个不同的索引 i 和 j，使得nums [i] 和nums [j]的差的绝对值最大为 t，并且 i 和 j 之间的差的绝对值最大为 ķ。c++，python，c#，java等语言的解法 工具/原料 c++，python，c#，java 方法/...
Can you solve this real interview question? Contains Duplicate - Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct. Example 1: Input: nums = [1,2,3,1] Output: tr
Contains Duplicate - Leetcode 217 - Python, 视频播放量 5、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 呼吸的chou, 作者简介 :),相关视频:【Python爬虫】手把手教你20行代码永久白嫖VIP付费电影,可分享源码,轻松实现看电影自由!python爬