【LeetCode】Contains Duplicate II 解题小结 题目:Given an array of integers and an integerk, find out whether there are two distinct indicesiandjin the array such that nums[i] = nums[j] and the difference betweeniandjis at mostk. 题目意思就是判断在一个数组中是否存在两个相同的元素,他们之...
from collections import Counter class Solution(object): def containsNearbyDuplicate(self, nums, k): """ :type nums: List[int] :type k: int :rtype: bool """ if k == 0: return False counter = Counter(nums) if len(counter) == len(nums): return False counter_gt1 = {num: count ...
LeetCode(43)-Contains Duplicate II 题目: 思路: 给定一个数组a,和一个整数k,题意是判断一个数组里面,有没有重复的两个元素,坐标是i和j,且i和j只差大于等于k。 考虑用hashMap 代码: <script type="text/javascript"> $(function () { $('pre.prettyprint code').each(function () { var lines ...
因为这里要判断 j−i<=k, 我们只需要使得 hash map的value保存最近的index就行。 见code: class Solution(object): def containsNearbyDuplicate(self, nums, k): """ :type nums: List[int] :type k: int :rtype: bool """ mydict = {} for i in xrange(len(nums)): if nums[i] in mydic...
class Solution { public boolean containsNearbyDuplicate(int[] nums, int k) { Map<Integer, Integer> table = new HashMap<>(); for (int i = 0; i < nums.length; i++) { if (table.containsKey(nums[i]) && i - table.get(nums[i]) <= k) { ...
Python自带的set让我觉得我是傻逼 classSolution:defcontainsDuplicate(self,nums:List[int])->bool:returnlen(nums)!=len(set(nums)) 分析 set 会自动去除重复项,所以一旦有重复项,array转set时长度就会变。 变了-> True,有重复数字 没变-> False,无重复数字...
Contains Duplicate - Leetcode 217 - Python, 视频播放量 5、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 呼吸的chou, 作者简介 :),相关视频:【Python爬虫】手把手教你20行代码永久白嫖VIP付费电影,可分享源码,轻松实现看电影自由!python爬
public class Solution {public bool ContainsNearbyAlmostDuplicate(int[] nums, int k, int t) {var len = nums.Length;var arr = nums.Select(((num, index) => new {num, index})).OrderBy(u => u.num).ToArray();for (int i = 0; i < len; i++)for (int j = i + 1; j < len...
题目链接: Contains Duplicate III: https://leetcode.com/problems/contains-duplicate-iii/ 存在重复元素 III: https://leetcode.cn/problems/contains-duplicate-iii/ LeetCode 日更第282天,感谢阅读至此的你 欢迎点赞、收藏、在看鼓励支持小满
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