利用IntStream接口,此接口是Java8的新特性,of()方法是将其内的参数转换为Stream,distinct()方法是去掉Stream中的重复元素,count()是对Stream中的元素记数。 publicbooleancontainsDuplicate5(int[] nums){returnIntStream.of(nums).distinct().count() < nums.length; } 07 有问题的一种解法 此解法是该道题目...
Contains Duplicate I Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 集合法 复杂度 时间O(N) 空间 O(N) 思路 用一个集合记录...
217. Contains Duplicate Java Solutin Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. Subscribeto see which companies asked this q...
Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. Example 1: Input: [1,2,3,1] Output: true Example 2: Input: [1,2,3,4...
import java.util.Set; public class Solution { public boolean containsDuplicate(int[] nums) { if (nums != null && nums.length > 1) { Set<Integer> set = new HashSet<>(nums.length); for(int i : nums) { if (set.contains(i)) { ...
URL https://leetcode.com/problems/contains-duplicate-iii/description/ 描述 Given an array of integers, find out whether there are two distinct indices i and j in the array such that the absolute differe...LeetCode 220. Contains Duplicate III 题目地址:https://leetcode.com/problems/contains-...
Contains Duplicate Desicription Given an array of integers, find if the array contains any duplicates
5 java解法。public boolean containsNearbyAlmostDuplicate(int[] nums, int k, int t) {if (t < 0) {return false;}TreeSet<Integer> set = new TreeSet<>();for (int i = 0; i < nums.length; i++) {// initially we fill the tree set (red black tree) with first k numbers// after...
AI代码解释 1// 219. Contains Duplicate II2// https://leetcode.com/problems/contains-duplicate-ii/description/3// 时间复杂度: O(n)4// 空间复杂度: O(k)5class Solution{6public:7boolcontainsNearbyDuplicate(vector<int>&nums,int k){89if(nums.size()<=1)returnfalse;1011if(k<=0)returnfals...
leetcode-220-存在重复元素III //示例中有整形溢出的问题,代码中强制转换为long long //使用了ceil操作(在容器中为lower_bound) class Solution { public: bool containsNearbyAlmostDuplicate(vector<int>& nums, int k, int t) { &...leetcode 219. Contains Duplicate II(存在重复元素 II)--Java题解 ...