Contains Duplicate I Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 集合法 复杂度 时间O(N) 空间 O(N) 思路 用一个集合记录...
}; 2.Java实现 classSolution {publicbooleancontainsDuplicate(int[] nums) { Arrays.sort(nums);intlen =nums.length;for(inti = 1;i<len;i++){if(nums[i]==nums[i-1])returntrue; }returnfalse; } } 3.哈希表实现 publicbooleancontainsDuplicate(int[] nums) {finalSet<Integer> distinct =newHash...
利用IntStream接口,此接口是Java8的新特性,of()方法是将其内的参数转换为Stream,distinct()方法是去掉Stream中的重复元素,count()是对Stream中的元素记数。 publicbooleancontainsDuplicate5(int[] nums){returnIntStream.of(nums).distinct().count() < nums.length; } 07 有问题的一种解法 此解法是该道题目...
class Solution { public boolean containsDuplicate(int[] nums) { Set<Integer> numbersSet = IntStream.of(nums) .boxed() .collect(Collectors.toSet()); return numbersSet.size() != nums.length; } } IntStream.of(nums)是Java 8中用于将整数数组转换为IntStream的方法。 在这个方法中,nums是一个整...
LeetCode Top Interview Questions 217. Contains Duplicate (Java版; Easy) 题目描述 Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct....
217. Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.
运行 AI代码解释 1// 219. Contains Duplicate II2// https://leetcode.com/problems/contains-duplicate-ii/description/3// 时间复杂度: O(n)4// 空间复杂度: O(k)5class Solution{6public:7boolcontainsNearbyDuplicate(vector<int>&nums,int k){89if(nums.size()<=1)returnfalse;1011if(k<=0)retu...
Contains Duplicate Desicription Given an array of integers, find if the array contains any duplicates
217. Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.
public class Solution {public bool ContainsNearbyAlmostDuplicate(int[] nums, int k, int t) {var len = nums.Length;var arr = nums.Select(((num, index) => new {num, index})).OrderBy(u => u.num).ToArray();for (int i = 0; i < len; i++)for (int j = i + 1; j < len...