Contains Duplicate III -leetcode Contains Duplicate III Given an array of integers, find out whether there are two distinct indicesiandjin the array such that the difference between nums[i] and nums[j] is at mosttand the difference betweeniandjis at mostk. 关于上述题意,我们可以转化为两个...
3.1 Java实现 publicclassSolution{publicbooleancontainsNearbyAlmostDuplicate(int[] nums,intk,intt){intn=nums.length; TreeSet<Long> set =newTreeSet<>();for(inti=0; i < n; i++) {Longceiling=set.ceiling((long) nums[i] - (long) t);if(ceiling !=null&& ceiling <= (long) nums[i] +...
Can you solve this real interview question? Contains Duplicate III - You are given an integer array nums and two integers indexDiff and valueDiff. Find a pair of indices (i, j) such that: * i != j, * abs(i - j) <= indexDiff. * abs(nums[i] - nums[j])
【摘要】 Leetcode 题目解析之 Contains Duplicate III Given an array of integers, find out whether there are two distinct indices i and j in the array such that the difference between numsi and numsj is at most t and the difference between i and j is at most k. 对于加入的元素,要能够在...
Remove(nums[i - indexDiff]) } } // 在循环中没有返回,则所有数都不满足题意 return false } 题目链接: Contains Duplicate III: leetcode.com/problems/c 存在重复元素 III: leetcode.cn/problems/co LeetCode 日更第 282 天,感谢阅读至此的你 欢迎点赞、收藏、在看鼓励支持小满...
LeetCode-220. Contains Duplicate III Given an array of integers, find out whether there are two distinct indicesiandjin the array such that theabsolutedifference betweennums[i]andnums[j]is at mosttand theabsolutedifference betweeniandjis at mostk....
[LeetCode] 220. Contains Duplicate III treemap Given an integer arraynumsand two integerskandt, returntrueif there are two distinct indicesiandjin the array such thatabs(nums[i] - nums[j]) <= tandabs(i - j) <= k. Example 1:...
it));if (min_diff <= t)return true;}return false;}3 运行时间16ms，超过了百分之82%的程序。这个程序还是可以的。4 c#解法。public class Solution {public bool ContainsNearbyAlmostDuplicate(int[] nums, int k, int t) {var len = nums.Length;var arr = nums.Select(((num, index) => new ...
func containsDuplicate(nums []int) bool { // 将 nums 转成集合 numSet := make(map[int]bool) for _, num := range nums { numSet[num] = true } // 集合的长度不等于 nums 的长度时,才含有重复数字 return len(numSet) != len(nums) } 题目链接: Contains Duplicate: leetcode.com/proble...
Can you solve this real interview question? Contains Duplicate - Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct. Example 1: Input: nums = [1,2,3,1] Output: tr