再进行递归就可以解决问题了。 1/**2* Definition for binary tree3* struct TreeNode {4* int val;5* TreeNode *left;6* TreeNode *right;7* TreeNode(int x) : val(x), left(NULL), right(NULL) {}8* };9*/10classSolution {11public:12TreeNode *buildTree(vector<int> &inorder, vector<...
Given inorder and postorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 思路: easy 算法: 1. public TreeNode buildTree(int[] inorder, int[] postorder) { 2. if (inorder == null || inorder.length == 0 || postorde...
TreeNode*buildTree(vector<int> &inorder, vector<int> &postorder) {if(inorder.size() ==0)returnNULL;introotval =postorder.back(); TreeNode*root =newTreeNode(rootval); vector<int>subv11, subv12, subv21, subv22;boolflag =true;for(inti =0; i < inorder.size(); ++i) {if(inor...
链接:https://leetcode.com/problems/construct-binary-tree-from-inorder-and-postorder-traversal/description/ 难度:Medium 题目:106. Construct Binary Tree from Inorder and Postorder Traversal Given inorder and postorder traversal of a tree, construct the binary tree. Note: You may assume that duplicat...
思路跟之间拿到inorder + preorder construct binary tree基本是一样的思路。根据postorder里最后面的是root的规律,我们维持一个postIndex从后面往前依次遍历postorder. 每次指向某个postorder里的元素,那我们就构建一个以该元素的值为val的tNode. 再去inorder里面找到这个tNode.val, 得到inIndex. 这样我们就可以把in...
inorder = [9,3,15,20,7] postorder = [9,15,7,20,3] 1. 2. Return the following binary tree: 3 / \ 9 20 / \ 15 7 1. 2. 3. 4. 5. 题解: 同105 classSolution{ public: TreeNode*buildTree(intpleft,intpright,intileft,intiright,vector<int>&postorder,vector<int>&inorder) { ...
Construct Binary Tree from Preorder and Inorder Traversal 题目描述(中等难度) 根据二叉树的先序遍历和中序遍历还原二叉树。 解法一 递归 先序遍历的顺序是根节点,左子树,右子树。中序遍历的顺序是左子树,根节点,右子树。 所以我们只需要根据先序遍历得到根节点,然后在中序遍历中找到根节点的位置,它的左边就...
106. 从中序与后序遍历序列构造二叉树 - 给定两个整数数组 inorder 和 postorder ,其中 inorder 是二叉树的中序遍历, postorder 是同一棵树的后序遍历,请你构造并返回这颗 二叉树 。 示例 1: [https://assets.leetcode.com/uploads/2021/02/19/tree.jpg] 输入:in
Construct Binary Search Tree from Preorder Traversal in Python - Suppose we have to create a binary search tree that matches the given preorder traversal. So if the pre-order traversal is like [8,5,1,7,10,12], then the output will be [8,5,10,1,7,null,12]
105. Construct Binary Tree from Preorder and Inorder Traversal 题目描述: Given preorder and inorder traversal of a tree, construct the binary tree. Example 1: null Note: You may assume that duplicates do not exist in the tree. 题目翻译 给定一个树的前序和中序遍历,构造二叉树。 示例1: ...