1) This is a complex math equation that involves complex numbers and an imaginary number. The complex numbers are {eq}(6hi + 2) {/eq} and {eq}(5i - 8) {/eq}. The purely imaginary number is {eq}5i {/eq}. The first step is to FOIL the right side of this equation: {eq}5i...
Prove that f(z)=-\frac{1}{2} (z+1/z) is a conformal map from the half-disc \{z = x+iy : \vert z\vert < 1, y>0\} to the upper half-plane. [Hint: The equation f(z)=w reduces to the quadratic equation z^2 +2wz +1=0, which has two distinct roots in \mathbb{C...
(c) Conclude, since ζ~ is given as an alternating series, that ζ has no zeros on the segment 0<σ<1. Extend this last assertion to σ=0 by using the functional equation. (a), 类似于Exercise 1的做法, 由于 ∑(−1)n 部分和恒有界, 因此 ζ~ 是右半复平面上的全纯函数.(b), 注...
The equation equals Eq. (1.189), but the form is not divided into two conjugated eigenvalues, which are now enclosed in the expanded range 2N, so that (3.39)λr=λr+N⁎ and (3.40)Rr=Rr+N⁎. The impulse response based on the model (3.38) is (see also Eq. (1.91)) (3.41)h(...
The equation of a hyperbola with a horizontal axis is (x2/ a2) - (y2 / b2) = 1 where a and b are positive constants.A circle has a constant distance from the center point, while a hyperbola is a curve that has two focus points (+ae, 0), and (-ae, 0).What is the ...
The equationXML_complex property specifies additional data for the equationXML property, as defined in section 2.3.2.10.
不等式是不能定义像实数域比较大小的不等式. 事实上, 如果复数域可以比较大小,那么必然推导出−1>0: hypothesisi>0⇒(i)2>0⇒(+i)2=−1>0⇒contradictionhypothesisi<0⇒−i>0⇒(−i)2=−1>0⇒contradiction soONLYreal number fieldRhas it'sinequalities. ...
That equation represents a `circle` with `center point (Cr-1,0)` and `radius R=Cr`. If we take into consideration that `|A|<1` then a `valid relation` should be something like `Cr<1`. Now we can go back to our main `code` in `Fortran` and select our `domain discretization`...
1 + 2 + 3 + … = − 1/12. This comes up often enough that I wanted to write a post that I could share a link to next time I see it. The equation is nonsense if interpreted in the usual way. The sum on the left diverges. You could say the sum is ∞ if by that you me...
When the roots are complex numbers—λ1=p+qi and λ2=p−qi, where p and q are real numbers—the two corresponding solutions of the differential equation ay″+by′+cy=0 are y1(t)=e(p+qi)t and y2(t)=e(p−qi)t. At this point, a crucial fact to know is Euler's formula,...