cryfor coordinating the round and being kind enough to offer a problem for the set andVladosiyafor statement translation; cowthecowandrangerscowboysfor their initial contribution to the problemset with unusedand impossibleproblems; the non finite amount of testers:Dominater069,Intellegent,-firefly-,Pr...
#include<set> #include<string> #include<cmath> #include<cstring> #defineFF first #defineSS second #definell long long #definepb push_back #definepm make_pair usingnamespacestd; typedefpair<int,int> PII; constintMAX =2e5+5; chars[MAX]; intn,a[MAX]; ll dp[MAX][5];//h a r d ...
Codeforces 1096D - Easy Problem - [DP] 题目链接:http://codeforces.com/problemset/problem/1096/D 题意: 给出一个小写字母组成的字符串,如果该字符串的某个子序列为hardhard,就代表这个字符串是不好的。 现在你要删掉若干字母,使得字符串是好的,同时删除第ii个字母会使得歧义程度增加a[i]a[i],你需要...
codeforces B. Ping-Pong (Easy Version) 解题报告 题目链接:http://codeforces.com/problemset/problem/320/B 题目意思:有两种操作:"1 x y"(x < y)和 "2 a b"(a ≠ b)。 问对于的"2 a b" 询问,能否从第a行的区间到达第b行的区间(行的数量是以:"1 x y" 来统计的,不包括"2 a ...
goes so I decided to start with posting video tutorials for as many problems from theCSES problem setas possible, as there are many videos out there which often explain solutions by going through way more details than needed or simply make understanding the problem way more complicated than ...
assign(n,-1);} bool unionSet(int x,int y){ x=root(x); y=root(y); if(x!=y){ //if(data[y] < data[x]) swap(x,y);//使用带权并查集时注释掉 data[x]+=data[y]; data[y]=x; } return x != y; } bool same(int x,int y) {return root(x)==root(y);} int root(...
Thus, you can hack somebody else's solution and earn points through it. After the contest all the solutions that have passed the pretests and haven't been hacked are tested on the final set of tests. The value of a task decreases during the contest (the faster you solve the problem, ...
Codeforces Round #540 (Div. 3):F1 - Tree Cutting (Easy Version) 题目链接:http://codeforces.com/contest/1118/problem/E 题意:现在有一棵树,树上的每个节点可以涂成红色、蓝色,或者不涂色,现在你可以删去一条边,将一棵树变成两棵树,两个树都只包含一种颜色。问这样的边又几个。 解题心得:dfs枚举...
( i 值与easy 中的mid 意义相同,代表要处理的 LCP 值)的所有起点插入到 set 当中,当然 z值=i 的起点要用 mp 记录,这里放进去的是 z值=i 的点而不是 z值\geq i 的点,原因在下一段落解释;之后同 easy 版本一样二分查找分段起点的位置,每找到一个就说明能多分一段,二分完就能求出对应的 LCP[i]...
absoluteelementitset You are given an array a consisting of n integers. You can perform the following operations arbitrary number of times (possibly, zero): dejavu1zz 2020/10/23 3500 codeforces 1382C1(思维) 编程算法 This is the easy version of the problem. The difference between the versions...