Easy Dynamic Problem List → Pay attention Before contest Codeforces Round (Div. 2) 5 days → Top contributors #UserContrib. 1cry162 2Dominater069159 3Qingyu158 3-is-this-fft-158 5atcoder_official156 6djm0317815
E1. Stars Drawing (Easy Edition) time limit per test3 seconds memory limit per test256 megabytes A star is a figure of the following type: an asterisk character '*' in the center of the figure and four rays (to the left, right, top, bottom) of the same positive length. The size ...
dp[i][x=0,1,2,3]dp[i][x=0,1,2,3]的状态是前ii个字母,第二维xx代表:00——不包含任何有可能构成 “hardhard” 的子序列;11——含有 “hh” 子序列;22——含有 “haha” 子序列;33——含有harhar子序列。 dp[i][x=0,1,2,3]dp[i][x=0,1,2,3]记录的值当然就是歧义程度。 转移的...
【Codeforces 1096D】Easy Problem 【链接】我是链接,点我呀:) 【题意】 让你将一个字符串删掉一些字符。 使得字符串中不包含子序列"hard" 删掉每个字符的代价已知为ai 让你求出代价最小的方法. 【题解】 设dp[i][j]表示前i个字符,已经和"hard"匹配前j个的最小花费。 对于dp[i][j] 对s[i+1]分类...
String Coloring (easy version) CodeForces - 1296E1(贪心) This is an easy version of the problem. The actual problems are different, but the easy version is almost a subtask of the hard version. Note that the constraints and the output format are different. ......
这道题的链接是:https://codeforces.com/contest/1400/problem/B 按照道理来说div2比赛当中的B题都不难,大概和LeetCode当中的Easy差不多,有时候要简单一些,有时候要难一些。一般来说属于大部分人都能做出来的题。但今天选的这道题有一点意外,它的通过人数比同一场的C题还要少。其实并不是它难,而是这题当中...
Canonforces is the Codeforces Problem of the Day codeforcescodeforces-apicodeforces-problemscodeforcespotdcodeforcesproblemoftheday UpdatedMay 20, 2024 JavaScript This is an Web App which will allow user to find the list of all problems the user did when he was Unrated Newbie Pupil Specialist and ...
1234B1-SocialNetworkEasyVersion.cpp 1234B2-SocialNetworkHardVersion.cpp 1234C-Pipes.cpp 1234D-DistinctCharactersQueries.cpp 1236A-Stones.cpp 1236B-AliceAndTheListOfPresents.cpp 1236C-Labs.cpp 1237A-BalancedRatingChanges.cpp 1237B-BalancedTunnel.cpp ...
1236B. Alice and the List of Presents 原题指路:codeforces.com/problems 题意 将n\ \ (1\leq n\leq 1\mathrm{e}9)种物品放入m\ \ (1\leq m\leq 1\mathrm{e}9)个不同的盒子中,要求:①每个盒子中不能出现相同的物品;②在m个背包中所有n种物品都出现过;③允许有空盒子.求方案数,答案对1\math...
This is the easy version of the problem. The difference between the versions is the constraint on n and the required number of operations. You can make hacks only if all versions of the problem are solved. There are two binary strings a and b of length n (a binary string is a string...