Easy Dynamic Problem List → Pay attention Before contest Codeforces Round (Div. 2) 5 days → Top contributors #UserContrib. 1cry162 2Dominater069159 3Qingyu158 3-is-this-fft-158 5atcoder_official156 6djm03178154 7errorgorn153 8adamant152...
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dp[i][x=0,1,2,3]dp[i][x=0,1,2,3]的状态是前ii个字母,第二维xx代表:00——不包含任何有可能构成 “hardhard” 的子序列;11——含有 “hh” 子序列;22——含有 “haha” 子序列;33——含有harhar子序列。 dp[i][x=0,1,2,3]dp[i][x=0,1,2,3]记录的值当然就是歧义程度。 转移的...
【Codeforces 1096D】Easy Problem 【链接】我是链接,点我呀:) 【题意】 让你将一个字符串删掉一些字符。 使得字符串中不包含子序列"hard" 删掉每个字符的代价已知为ai 让你求出代价最小的方法. 【题解】 设dp[i][j]表示前i个字符,已经和"hard"匹配前j个的最小花费。 对于dp[i][j] 对s[i+1]分类...
这道题的链接是:https://codeforces.com/contest/1400/problem/B 按照道理来说div2比赛当中的B题都不难,大概和LeetCode当中的Easy差不多,有时候要简单一些,有时候要难一些。一般来说属于大部分人都能做出来的题。但今天选的这道题有一点意外,它的通过人数比同一场的C题还要少。其实并不是它难,而是这题当中...
题目链接:https://codeforces.com/contest/1419/problem/D2 多说一句一般来说一场比赛当中题目都是一个字母,怎么今天这道题是D2呢?这是因为这道题出题人给了两个版本,一个Easy版和一个Hard版。 废话不多说,我们来看题目。 题意 有一个叫Sage的妹子过生日,她准备买一点冰激凌吃,但是她有一个奇怪的要求就是...
Canonforces is the Codeforces Problem of the Day codeforcescodeforces-apicodeforces-problemscodeforcespotdcodeforcesproblemoftheday UpdatedMay 20, 2024 JavaScript This is an Web App which will allow user to find the list of all problems the user did when he was Unrated Newbie Pupil Specialist and ...
1234B1-SocialNetworkEasyVersion.cpp 1234B2-SocialNetworkHardVersion.cpp 1234C-Pipes.cpp 1234D-DistinctCharactersQueries.cpp 1236A-Stones.cpp 1236B-AliceAndTheListOfPresents.cpp 1236C-Labs.cpp 1237A-BalancedRatingChanges.cpp 1237B-BalancedTunnel.cpp ...
This is the easy version of the problem. The difference between the versions is the constraint on n and the required number of operations. You can make hacks only if all versions of the problem are solved. There are two binary strings a and b of length n (a binary string is a string...
This problem is also simple. Actually, most of the 'A' problems (usually the first one) in codeforces contests are easy to solve. I choose these problems to boost my confidences :) and learn python. The problem is even easier. Because the array is alread