25 is a valid perfect square True 23 is a valid perfect square False Conclusion In this post, we saw one of the coding questions that are usually asked in interviews. Let us know how you would approach this pro
Let's see the implementation of the above algorithm in the Python program. Python program to check the given date is valid or not # Importing datetime moduleimportdatetime# Input the date as integers and mapping# it to store the values to d, m, and y variablesd,m,y=map(int,input("Ent...
//C# program to check the given number is a//perfect number or not.usingSystem;classCheckPerfect{staticboolIsPerfect(intnumber){intsum=0;intiLoop=0;for(iLoop=1;iLoop<number;iLoop++){if(number%iLoop==0)sum=sum+iLoop;}if(sum==number){returntrue;}returnfalse;}staticvoidMain(string[]args)...
I’m well aware that some points are not as most efficient as possible, but while writing I liked the idea of describing the process more than building the perfect solution.What do you think about this? Give me your opinion about it and let’s discuss your solutions in the comments!
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Move a piece or pawn to a square where it attacks (the opposing king) He moves his knight to check my king again Review To consider retrospectively; look back on Reviewed the day's events. Check (in poker) choose not to make a bet when called upon, allowing another player to do so ...
The check mark button emoji ✅ is a white checkmark inside a green square. It symbolizes confirmation, accomplishment, or successfully completing tasks. Often used to show something is done, approved, or verified, it’s perfect for to-do lists, project updates, or marking things as correct....
# Python program to check prime number # Function to check prime number def isPrime(n): return all([(n % j) for j in range(2, int(n/2)+1)]) and n>1 # Main code num = 59 if isPrime(num): print(num, "is a prime number") else: print(num, "is not a prime number") ...
#include <bits/stdc++.h> using namespace std; int isSquare(int k){ // if k isn't perfect square then the square root //will be a float value but we are rounding it off to integer int s=sqrt(k); // only in case of perfect square there //will not be any rounding off error ...