printf("The average of the array is: %.2f\n", avg);return 0;} 案例3：判断一个数是否为素数 #include <stdio.h> #include <stdbool.h> bool isPrime(int number) { if (number <= 1) { return false;} for (int i = 2; i <= number /
(n <= 0) return 0; return arr[n - 1] + sum_array(arr, n - 1); } int main() { int arr[] = {1, 2, 3, 4, 5}; int n = sizeof(arr) / sizeof(arr[0]); int sum = sum_array(arr, n); double average = (double)sum / n; printf("Average: %.2f\n", average); ...
输入数字: ", i+1); scanf("%f", &num[i]); sum += num[i]; } average = sum / n; printf("平均值 = %.2f", average); return 0; }输出结果为:输入元素个数: 4 1. 输入数字: 1 2. 输入数字: 2 3. 输入数字: 4 4. 输入数字: 8 平均值 = 3.75...
//如下写法正确:float average(float array[]) 定义的average函数,形参数组不指定大小 /* 以上原因的本质是:系统对源程序进行编译时,编译系统会把形参数组处理为指针变量 即把float array[] 转换为float * array,该指针变量用来接收从实参数组传过来的地址 所以以上两者是等价的,对数组元素的访问,用下标和指针也是...
dataType 为数据类型,arrayName 为数组名称,length 为数组长度。 1 2 3 4 5 6 7 8 9 10 11 #include <stdio.h> intmain(){ intnums[10]; //依次输出数组元素 for(inti=0; i<10; i++){ printf("%d ", nums[i]); } return0;
i in s: sum = sum + 1 #元素个数 all = all + i average = all / sum ...
Here, we have computed the average ofnnumbers entered by the user. Access elements out of its bound! Suppose you declared an array of 10 elements. Let's say, int testArray[10]; You can access the array elements fromtestArray[0]totestArray[9]. ...
("\nThe yearly average is %.1f inches.\n\n",total/YEARS);printf("MONTHLY AVERAGE:\n\n");printf(" Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec \n");for(month=0;month<MONTHS;month++){for(year=0,subtot=0;year<YEARS;year++){subtot+=rain[year][month];}printf("%4.1f",...
在C语言中,calculate_average 是一个描述性函数名,用于计算一组数值的平均值。以下是一个完整的实现示例,包括函数定义和调用: 示例代码:计算平均值 c #include <wap.dggkj.com> // 函数声明 double calculate_average(const double *array, int size); ...