Mean of Matrix Rows Copy Code Copy Command Create a matrix and compute the mean of each row. Get A = [0 1 1; 2 3 2; 3 0 1; 1 2 3] A = 4×3 0 1 1 2 3 2 3 0 1 1 2 3 Get M = mean(A,2) M = 4×1 0.6667 2.3333 1.3
Mean of Matrix Rows Copy Code Copy Command Create a matrix and compute the mean of each row. Get A = [0 1 1; 2 3 2; 3 0 1; 1 2 3] A = 4×3 0 1 1 2 3 2 3 0 1 1 2 3 Get M = mean(A,2) M = 4×1 0.6667 2.3333 1.3333 2.0000 Mean of 3-D Array Copy ...
Average or mean value of array collapse all in page Syntax M = mean(A) M = mean(A,"all") M = mean(A,dim) M = mean(A,vecdim) M = mean(___,outtype) M = mean(___,missingflag) M = mean(___,Weights=W) Description ...
Average or mean value of array collapse all in page Description M = mean(A)returns themeanof the elements ofAalong the first array dimension whose size does not equal 1. IfAis a vector, thenmean(A)returns the mean of the elements. ...
Actually, I didn't exlain my question very well. Actually I want to take average of elemnet of array. So Z = 6×2 cell array {[1 0 2 2 1 1 3 1 1 0]} {[2 1 0 0 0 1 0 2 0 0]} {[2 2 3 3 1 3 3 2 1 0]} {[2 2 0 0 1 2 0 2 0 0]} ...
This MATLAB function returns the mean of the elements of A along the first array dimension whose size does not equal 1.
M = mean(A) computes the mean value of the real-valued fixed-point array A along its first nonsingleton dimension. example M = mean(A,dim) computes the mean value of the real-valued fixed-point array A along dimension dim. dim must be a positive, real-valued integer with a power-of...
So i have to make dynamic vectors with 3 dimentions and calculate the average of the sum of all vector's, how can I do this? example: 테마복사 if true V = []; for i=1:5 V1 = [v1 v2 v3] V2 = [v1 v2 v3] V3 = [v1 v2 v3] V4 = [v1 v2 v3] V5 = [v1 ...
function[sumArray,averageArray,minArray]=arraystuff(inputArray)sumArray=sum(sum(inputArray));averageArray=mean(mean(inputArray));minArray=min(min(inputArray));end 代码语言:javascript 代码运行次数:0 运行 AI代码解释 [Asum,Aavg,Amin]=cellfun(@arraystuff,A)Asum=45.00003.00007.3668Aavg=5.00000.33330.613...
averageArray = mean(mean(inputArray)); minArray = min(min(inputArray)); end 1. 2. 3. 4. 5. [Asum, Aavg, Amin] = cellfun(@arraystuff,A) Asum = 45.0000 3.0000 7.3668 Aavg = 5.0000 0.3333 0.6139 Amin = 1.0000 0 0.0975 1.