def count_files_in_folder(prefix): total = 0 keys = s3_client.list_objects(Bucket=bucket_name, Prefix=prefix) for key in keys['Contents']: if key['Key'][-1:] != '/': total += 1 return total 在这种情况下,总数为 4。 如果我刚刚做了 count = len(s3_client.list_objects(Bucket...
上面的代码使用了MaxKeys=1。这样效率更高。即使文件夹包含很多文件，它也会快速地响应其中的一个内容。
我正在使用 boto3 从 s3 存储桶中获取文件。我需要类似的功能,例如 aws s3 sync 我目前的代码是 #!/usr/bin/python import boto3 s3=boto3.client('s3') list=s3.list_objects(Bucket='my_bucket_name')['Contents'] for key in list: s3.download_file('my_bucket_name', key['Key'], key['Key...
上面的代码使用了MaxKeys=1。这样效率更高。即使文件夹包含很多文件，它也会快速地响应其中的一个内容。
"" resp = s3.list_objects_v2(Bucket=bucket, Prefix=prefix) for obj in resp['Contents']: files = obj['Key'] print(files) return files filename = get_s3_keys('your_bucket_name', 'folder_name/sub_folder_name/') print(filename) 更新:最简单的方法是使用awswrangler import awswrangler...
files.append((name, key.name, False, key.size, last_modified)) try: paginator = self.s3_client.get_paginator("list_objects_v2") for page in paginator.paginate( Bucket=self.bucket_name, Prefix=path, Delimiter=self.separator ): for common_prefix in page.get("CommonPrefixes", []): name...
import boto3 s3 = boto3.client('s3') 使用list_objects_v2方法列出指定存储桶中的所有对象: 代码语言:txt 复制 response = s3.list_objects_v2(Bucket='your_bucket_name') 遍历返回的对象列表,筛选出名称包含指定子文件夹的对象: 代码语言:txt 复制 folder_name = 'your_folder_name' files = [] ...
Issues listImage corruption when uploading to S3 using Boto3 in Lambda bug lambda p2 s3 #4229 opened Aug 6, 2024 by RyanFitzSimmonsAK 2 Bucket name sometimes missing in the S3 URL - causing failures for the same bucket and code that was previously successful for operations like get ...
读取S3某个路径下的所有objects也有一个坑,就是默认单次get object的上限是1000个,所以如果想做到full list,也需要做特定的处理。 defget_all_s3_objects(s3,**base_kwargs):""" Private method to list all files under path :param s3: s3 client using boto3.client('s3') ...
上一期的程序 Sub FileDialog_sample1() With Application.FileDialog(msoFileDialogFolderPicker) .Initial...