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解析(1)设光线BM在M点的入射角为i,折射角为r,由几何知识可知,i = 30°, r = 60°,根据折射定律得 sin n=~?~ sin 代入数据得n=\:3② ⑵光线BN恰好在N点发生全反射,则NBN0为临界角C sin C=n③ 设球心到BN的距离为d,由几何知识可知d=Rsin C④ ...
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6EP1336-2BA10 1 6GK5008-0BA10-1AB2 1 6GK1901-1BB10-2AB0 10有货的联系 详细 接触器触点|LA5FG431 5 有的联系 详细 6AV2128-3XB06-0AX1 1 有货的留言 详细 6SL3131-6TE21-6AA3 6SL3121-2TE15-0AA3 6SL3121-2TE21-0AA3 6FC5371-0AA30-0AB0有的联系 详细 6GT2800-4BB00*10 6ES7...
规格型号 9256 SGS-M1013236 FSR-16150731 HP-2519181 DSNU-8-80-P-A9582 SG-M42X234580 YSRF-S-12-C539638 YSRP-8157304 FUA-50176877 HUA-40-R3529354 HPV-22-60-A2895924 CRSNCS-80560253 ZBV-9-8178456 KP-12-60014962 WSR-32-J535585 HGP-SL10-25...
已知函数f(x)=(x-1)2,数列{an}是公差为d的等差数列,数列{bn}是公比为q(q∈R且q≠1)的等比数列.若a1=f(d-1),a3=f(d+1),b1=f(q-1),b3=f(q+1)(1)求数列{an},{bn}的通项公式;(2)设数列{Cn}对任意正整数n均有 C1 b1+ C2 b2+…+ Cn bn=an+1成立,求{Cn}的通项;(3)试比较 ...
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VM-BPL30 VM-BPL60 JVC BN-V607 BN-V607U BN-V615 BN-V615U BN-V615X BN-V812 BN-V812U BN-V814 BN-V814U PANASONIC AG-BP15P CGR-B/202 CGR-B/202A1B CGR-B/202E1B CGR-B/403 CGR-B/814 CGR-B202A PV-DBP5 VW-B202 VW-VBD1 VW-VBD1E VW-VBD2 VW-VBD2E RCA BB-65L SONY...
1 3 1 3 2 n 1 Sn n(a1+an) 2 n2 2 bn=an- 2 bnk k bnk bn1 1 q= bn2 bn1 = 3 1 =3 bnk=2•3k-1 k k-1 nk=3k-1 r s t as2=ar•at 2 )2 2 2 (rt-s2) 2 =2s-r-t 2 2 2s-r-t rt-s2 * 2s-r-t
PLM-A35(Glasstron)PLM-A55(Glasstron)Q002-HDR1 UPX-2000(Printer) Battery Replace Code HITACHI VM-BPL13VM-BPL13AVM-BPL13J VM-BPL27VM-BPL27AVM-BPL30 VM-BPL60 JVC BN-V607BN-V607UBN-V812 BN-V812UBN-V814BN-V814U PANASONIC AG-BP15PCGR-B/202CGR-B/202A1B ...