1//Recursive C program for level order traversal of Binary Tree2#include <stdio.h>3#include <stdlib.h>45structnode6{7intdata;8structnode *left;9structnode *right;10};1112structnode* newNode(intdata)13{14structnode *node = (structnode*)malloc(sizeof(structnode));15node->data =data;16...
}/*** NLR:前序遍历(Preorder Traversal 亦称(先序遍历)) * 访问根结点的操作发生在遍历其左右子树之前。*/publicvoidpreOrderTraversal() {//NSystem.out.print(this);//Lif(this.leftSubNode !=null) {this.leftSubNode.preOrderTraversal(); }//Rif(this.rightSubNode !=null) {this.rightSubNode.p...
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vector<int> inorderTraversal(TreeNode* root) { vector<int> vec; if(root == NULL)return vec; inorder(root,vec); return vec; } }; 递归 class Solution { public: void inorder(TreeNode* root, vector<int> & vec) { if(root -> left != NULL) { inorder(root -> left,vec); } vec...
Binary Tree Level Order Traversal(二叉树的层次遍历) HoneyMoose iSharkFly - 鲨鱼君 来自专栏 · Java 描述给出一棵二叉树,返回其节点值的层次遍历(逐层从左往右访问)样例给一棵二叉树 {3,9,20,#,#,15,7}:3 / \ 9 20 / \ 15 7返回他的分层遍历结果:[ [3], [9,20], [15,7] ]挑战挑战1...
push(NULL); 29 int nLevelCount = 1; 30 while (true) { 31 TreeNode *pTemp = tree_queue.front(); 32 tree_queue.pop(); 33 if (pTemp == NULL) { 34 if (nLevelCount%2 == 0) { //if the num of level is odd, swap the ivec; 35 Swap(ivec); 36 } 37 tree_vector.push_...
new_node->right = NULL; return new_node; } void tree::levelorder_traversal(node *root){ queue <node*> que; node *item; que.push(root); //insert the root at first while(!que.empty()){ item = que.front(); //get the element from the front end cout << item->value << " "...
Tree traversalis the process of visiting each node in the tree exactly once. Visiting each node in a graph should be done in a systematic manner. If search result in a visit to all the vertices, it is called a traversal. There are basically three traversal techniques for a binary tree th...
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If we are given a binary tree and we need to perform a vertical order traversal, that means we will be processing the nodes of the binary tree from left to right. Suppose we have a tree such as the one given below. If we traverse the tree in vertical order and print the nodes then...