*right;9bt_node(intval =0)10: value(val), left(NULL), right(NULL) {}11};1213voidprocess(bt_node*pnode) {14if(pnode !=NULL)15cout << pnode->value <<"";16}1718//A119voidrecursive_inorder_traversal(bt_node*root) {20if(root !=NULL) {21recursive...
}/*** LNR:中序遍历(Inorder Traversal) * 访问根结点的操作发生在遍历其左右子树之中(间)。*/publicvoidinOrderTraversal() {//Lif(this.leftSubNode !=null) {this.leftSubNode.inOrderTraversal(); }//NSystem.out.print(this);//Rif(this.rightSubNode !=null) {this.rightSubNode.inOrderTraversal...
inorder(root -> right,vec); } } vector<int> inorderTraversal(TreeNode* root) { vector<int> vec; if(root == NULL)return vec; inorder(root,vec); return vec; } }; 递归 class Solution { public: void inorder(TreeNode* root, vector<int> & vec) { if(root -> left != NULL) {...
Leetcode 94 binary tree inorder traversal 思路是从根节点开始,先将根节点压入栈,然后再将其所有左子结点压入栈,然后取出栈顶节点,保存节点值,再将当前指针移到其右子节点上,若存在右子节点,则在下次循环时又可将其所有左子结点压入栈中。这样就保证了访问顺序为左-根-右。 Leetcode 145 binary tree po...
方法一: 使用 LeetCode: 102. Binary Tree Level Order Traversal 的方法。在偶数次写入时,翻转写入的序列。 方法二: 使用两个栈存每行的数据,奇数行先存左孩子,再存右孩子,偶数行先存右孩子,再存左孩子。 AC 代码 方法一 /** ...
In Part 1, we looked at what data structures are, how their performance can be evaluated, and how these performance considerations play into choosing which data structure to utilize for a particular algorithm. In addition to reviewing the basics of data structures and their analysis, we also loo...
In Part 1, we looked at what data structures are, how their performance can be evaluated, and how these performance considerations play into choosing which data structure to utilize for a particular algorithm. In addition to reviewing the basics of data structures and their analysis, we also loo...
#include<cstdio> #include<cstring> #include<iostream> #include<algorithm> using namespace std; typedef unsigned long long LL; const int mod = 1e9 + 7; const int maxn = 1e3 + 10; int n, a[maxn], b[maxn], tot; void dfs(int x) ...
binarytreetraversal.zipFl**末初 上传8.5 KB 文件格式 zip 二叉树遍历算法实现(Python) 点赞(0) 踩踩(0) 反馈 所需:1 积分 电信网络下载 Option_Trend 2025-04-02 00:00:16 积分:1 stock-ai-pc 2025-04-02 00:00:54 积分:1 DSPCourseDesign 2025-04-02 00:07:08 积分:1 anime-kawai-...
classSolution{public:vector<int>inorderTraversal(TreeNode*root){vector<int>result;stack<TreeNode*>st;TreeNode*p=root;while(!st.empty()||p){if(p!=NULL){st.push(p);p=p->left;}else{TreeNode*top=st.top();st.pop();result.push_back(top->val);p=top->right;}}returnresult;}}; ...