1、题目描述 2、问题分析 使用递归 3、代码 1TreeNode* pruneTree(TreeNode*root) {2if(root ==NULL)3returnNULL;4prun(root);5returnroot;6}78voidprun(TreeNode *root)9{10if(root ==NULL)11return;12if(!has_ones(root->left))13root->left =NULL;1415if(!has_ones(root->right))16root->ri...
NULL : root; } }; Github 同步地址: https://github.com/grandyang/leetcode/issues/814 参考资料: https://leetcode.com/problems/binary-tree-pruning/ https://leetcode.com/problems/binary-tree-pruning/discuss/122730/C++JavaPython-Self-Explaining-Solution-and-2-lines LeetCode All in One 题目讲解...
Can you solve this real interview question? Binary Tree Pruning - Given the root of a binary tree, return the same tree where every subtree (of the given tree) not containing a 1 has been removed. A subtree of a node node is node plus every node that is
Left != nil || root.Right != nil { return root } // 此时当前子树中的所有子结点都是 0 ,需要修剪掉 return nil } 题目链接: Binary Tree Pruning: leetcode.com/problems/b 二叉树剪枝: leetcode.cn/problems/bi LeetCode 日更第 235 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满...
A clever solution exists. Isn't this O(n2), though? It's also a leetcode problem.The in-order traversal gives you an ordering of the elements. You can reconstruct the original binary tree by adding elements to a binary search tree in the pre-order traversal order, with "<=>" ...
【LeetCode】二叉树剪枝搜索(Binary Tree Pruning) 原题网址(中):https://leetcode-cn.com/problems/binary-tree-pruning/ 原题网址(英):https://leetcode.com/problems/binary-tree-pruning/ 题目: We are given the head node root of a binary tree, where additionally every node’s value is either ...
Leetcode 814. Binary Tree Pruning dfs 要点是这一句: returnnode.val==1ornode.leftornode.right 完整代码: #Definition for a binary tree node.#class TreeNode:#def __init__(self, x):#self.val = x#self.left = None#self.right = NoneimportfunctoolsclassSolution:...
左右孩子为None22将该结点置为None23"""24classTreeNode:25def__init__(self, x):26self.val =x27self.left =None28self.right =None2930classSolution:31defpruneTree(self, root):32ifroot ==None:33returnNone34root.left =self.pruneTree(root.left)35root.right =self.pruneTree(root.right)36if...
TreeDepth-first Search 链接:http://leetcode.com/problems/balanced-binary-tree/ 题解: 求一棵树是否是平衡树。根据定义计算两个子节点的深度,当深度差大于1时返回false,依然是DFS。 Time Complexity - O(n), Space Complexity - O(n) publicclassSolution {publicbooleanisBalanced(TreeNode root) {returnge...
[LeetCode] Binary Tree Pruning We are given the head noderootof a binary tree, where additionally every node's value is either a 0 or a 1. Return the same tree where every subtree (of the given tree) not containing a 1 has been removed....