Left != nil || root.Right != nil { return root } // 此时当前子树中的所有子结点都是 0 ,需要修剪掉 return nil } 题目链接: Binary Tree Pruning: leetcode.com/problems/b 二叉树剪枝: leetcode.cn/problems/bi LeetCode 日更第 235 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满...
2、问题分析 使用递归 3、代码 1TreeNode* pruneTree(TreeNode*root) {2if(root ==NULL)3returnNULL;4prun(root);5returnroot;6}78voidprun(TreeNode *root)9{10if(root ==NULL)11return;12if(!has_ones(root->left))13root->left =NULL;1415if(!has_ones(root->right))16root->right =NULL;17...
原题网址(英):https://leetcode.com/problems/binary-tree-pruning/ 题目: We are given the head node root of a binary tree, where additionally every node’s value is either a 0 or a 1. Return the same tree where every subtree (of the given tree) not containing a 1 has been removed. ...
Can you solve this real interview question? Binary Tree Pruning - Given the root of a binary tree, return the same tree where every subtree (of the given tree) not containing a 1 has been removed. A subtree of a node node is node plus every node that is
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It's also a leetcode problem.The in-order traversal gives you an ordering of the elements. You can reconstruct the original binary tree by adding elements to a binary search tree in the pre-order traversal order, with "<=>" determined by the in-order traversal, instead of using <, >,...
We are given the head node root of a binary tree, where additionally every node’s value is either a 0 or a 1. Return the same tree where every subtree (of the given tree) not containing a 1 has been removed. (Recall that the subtree of a node X is X, plus every node that is...
The binary tree will have at most100 nodes. The value of each node will only be0or1. 这道题给了一棵二叉树,说是结点只有0或者1,让我们移除所有没有含有结点1的子树。题目中也给了一些图例,不难理解。这道题的难点就在于怎么看待没有结点1的子树,由于子树也是由一个个结点组成的,需要明确的是一个...
Leetcode 814. Binary Tree Pruning dfs 要点是这一句: returnnode.val==1ornode.leftornode.right 完整代码: #Definition for a binary tree node.#class TreeNode:#def __init__(self, x):#self.val = x#self.left = None#self.right = NoneimportfunctoolsclassSolution:...
1 """ 2 We are given the head node root of a binary tree, where additionally every node's value is either a 0 or a 1. 3 Return the