* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {public: vector<int> postorderTraversal(TreeNode *root) { vector<int>result;if(root==NULL)returnresult; stack<TreeNode*>pTree; pTree.push(root);while(!pTree.empty()) { TreeNode*curNode=pTree.top();...
*/vector<int>postorderTraversal(TreeNode * root){// write your code herevector<int> result; traverse(root, result);returnresult; }// 遍历法的递归函数,没有返回值,函数参数result贯穿整个递归过程用来记录遍历的结果voidtraverse(TreeNode * root,vector<int> & result)// 递归三要素之定义{if(root =...
left); traversal(root.right); result.add(root.val); } } 复杂度分析 时间复杂度:O(n),其中 n 是二叉树的节点数。每一个节点恰好被遍历一次 空间复杂度:O(n),为递归过程中栈的开销,平均情况下为 O(logn),最坏情况下树呈现链状,为 O(n) 迭代法 /** * Definition for a binary tree node....
publicList<Integer>postorderTraversal(TreeNoderoot){List<Integer>list=newArrayList<>();if(root==null){returnlist;}Stack<TreeNode>stack=newStack<>();stack.push(root);stack.push(root);while(!stack.isEmpty()){TreeNodecur=stack.pop();if(cur==null){continue;}if(!stack.isEmpty()&&cur==stac...
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: //非递归方法实现后序遍历 vector<int> postorderTraversal(TreeNode* root) { vector<int> res; if(root==NULL) return res; stack<TreeNode *> vis; ...
给定一个二叉树,返回它的后序遍历。 示例: 输入:[1,null,2,3] 1 \ 2 / 3输出:[3,2,1] 1. 2. 3. 4. 5. 6. 7. 8. 进阶:递归算法很简单,你可以通过迭代算法完成吗? DFS 今天这道题比较简单,直接DFS就可以了。 Code def postorderTraversal(self, root: TreeNode) -> List[int]: ...
1) Preorder traversal Totraverse a binary tree in preorder, following operations are carried out: Visit the root. Traverse the left sub tree of root. Traverse the right sub tree of root. Note:Preorder traversal is also known as NLR traversal. ...
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ...
binarytreetraversal.zipFl**末初 上传8.5 KB 文件格式 zip 二叉树遍历算法实现(Python) 点赞(0) 踩踩(0) 反馈 所需:1 积分 电信网络下载 Option_Trend 2025-04-02 00:00:16 积分:1 stock-ai-pc 2025-04-02 00:00:54 积分:1 DSPCourseDesign 2025-04-02 00:07:08 积分:1 anime-kawai-...
*/class Solution{public:vector<int>postorderTraversal(TreeNode*root){vector<int>res;if(!root)returnres;stack<TreeNode*>st;st.push(root);while(st.size()){TreeNode*temp=st.top();st.pop();res.push_back(temp->val);if(temp->left)st.push(temp->left);if(temp->right)st.push(temp->ri...