binaryTree.postOrderTraversal(); }publicstaticclassBinaryTree {privateNode root;publicvoidpreOrderTraversal() {this.root.preOrderTraversal(); }publicvoidinOrderTraversal() {this.root.inOrderTraversal(); }publicvoidpostOrderTraversal() {this.root.postOrderTraversal(); }publicBinaryTree(Node root) {...
1classSolution {2public:3vector<int> inorderTraversal(TreeNode *root) {4vector<int>result;5TreeNode *p =root;6while(p) {7if(p->left) {8TreeNode *q = p->left;9while(q->right && q->right !=p) {10q = q->right;11}12if(q->right ==p) {13result.push_back(p->val);14q-...
题目: Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 根据前序遍历和中序遍历结果构造二叉树。 思路分析: 分析二叉树前序遍历和中序遍历的结果我们发现: 二叉树前序遍历的第一个节点是根节点。 在中序遍历...
publicList<Integer>inorderTraversal(TreeNoderoot){List<Integer>ans=newArrayList<>();Stack<TreeNode>stack=newStack<>();TreeNodecur=root;while(cur!=null||!stack.isEmpty()){//节点不为空一直压栈while(cur!=null){stack.push(cur);cur=cur.left;//考虑左子树}//节点为空,就出栈cur=stack.pop()...
(Stringdata){// NULL CHECKif(data.equals("{}")){returnnull;}ArrayList<TreeNode>treeList=newArrayList<TreeNode>();data=data.replace("{","");data=data.replace("}","");String[]vals=data.split(",");// INSERT ROOTTreeNoderoot=newTreeNode(Integer.parseInt(vals[0]));treeList.add(root...
Binary Tree Level Order Traversal Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 代码语言:javascript ...
Note: Inorder traversal is also known as LNR traversal.Algorithm:Algorithm inorder(t) /*t is a binary tree. Each node of t has three fields: lchild, data, and rchild.*/ { If t! =0 then { Inorder(t->lchild); Visit(t); Inorder(t->rchild); } } ...
Given preorder and inorder traversal of a tree, construct the binary tree. 二分法 复杂度 时间O(N^2) 空间 O(N) 思路 我们先考察先序遍历序列和中序遍历序列的特点。对于先序遍历序列,根在最前面,后面部分存在一个分割点,前半部分是根的左子树,后半部分是根的右子树。对于中序遍历序列,根在中间部分...
5 "empty" nodes (value 0 by default). Based on HUFFVAL table with 4 total values: 1 value of 2 bits length, 2 values of 3 bits length and 1 value of 4 bits length. Roots correspond to values in the HUFFVAL table. Nodes added via preorder traversal, removed via postorder traversal...
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