leetcode 930. Binary Subarrays With Sum This remains me of some 'subarray count' type problems….. classSolution{publicintnumSubarraysWithSum(int[] A,intS){int[] ps =newint[A.length +1]; ps[0] =1;intsum=0;intret=0;for(intv: A) { sum += v;if(sum - S >=0) { ret +...
If sum >= S, then res += count[sum-S]. Because, there must be t, t<i, sum from 0 to t is sum-S, from t to i is S. Then count of S is count of sum-S. Time Complexity: O(n). n = A.length. Space: O(n). AC Java: 1classSolution {2publicintnumSubarraysWithSum(...
public int numSubarraysWithSum(int[] A, int S) { if (A.length == 0) return 0; int result = 0; int[] sumOne = new int[A.length]; int st = 0; int ed = 0; sumOne[0] = A[0] == 1 ? 1 : 0; for (int i = 1; i < A.length; i++) { sumOne[i] = A[i] =...
public:intnumSubarraysWithSum(vector<int>& A,intS) {intres =0,sum=0, left =0, n = A.size();for(inti =0; i < n; ++i) {sum+= A[i];while(left < i &∑> S)sum-= A[left++];if(sum< S)continue;if(sum== S) ++res;for(intj = left; j < i && A[j] ==0; ++j)...
题目地址:https://leetcode.com/problems/binary-subarrays-with-sum/description/ 题目描述 In an arrayAof0s and1s, how manynon-emptysubarrays have sumS? Example 1: Input: A = [1,0,1,0,1], S =2Output:4Explanation: The4subarrays are bolded below: ...
public int numSubarraysWithSum(int[]A,intS) { return atMost(A,S) - atMost(A,S- 1); } private int atMost(int[]A,intS) { if (S< 0) return 0; int res = 0, n =A.length; for (inti= 0,j= 0;j<n; ++j) {S-=A[j]; ...
0 <= S <= A.length A[i]为0或1 220ms 1classSolution {2func numSubarraysWithSum(_ A: [Int], _ S: Int) ->Int {3varn:Int =A.count4varcum:[Int] = [Int](repeating:0,count: n +1)5foriin0..<n6{7cum[i +1] = cum[i] +A[i]8}910varret:Int =011varf:[Int] = [...