* and the index of the last number*/vector<int> subarraySum(vector<int>nums){ vector<int>result;//curr_sum for the first item, index for the second itemmap<int,int>hash; hash[0] =0;intcurr_sum =0;for(inti =0; i != nums.size(); ++i) { curr_sum+=nums[i];if(hash.find(...
Q: Given an array of positive and negative integers find the first subarray with zero sum? no 0's will be a part of the input array and handle all the edge cases A: 1. iterate through the array once, and take the sum from 0 to every other index of the array. 2. If any sum i...
Subarray with sum less than k 和乘法其实类似, 假设均为正数的话 int maxSubarrayLessThanK(vector<int>& nums, int k){ int ans=0; long long sum=0; for(int i=0, left=0; i<int(nums.size()); i++){ sum+=nums[i]; while(sum>=k) sum-=nums[left++]; ans=max(ans, i-left+1)...
Given an integer array, find a subarray with sum closest to zero. Return the indexes of the first number and last number. Example Given [-3, 1, 1, -3, 5], return [0, 2], [1, 3], [1, 1], [2, 2] or [0, 4]. Challenge O(nlogn) time 这题个人感觉比较难; 思路: 1.求...
Version 2,采用动态规划求解,首先定义状态,dp[i]是以nums[i]为结尾的连续子数组的最大和,状态转移方程为:如果dp[i-1]>0,无论nums[i]是什么数,以nums[i]为结尾的连续子数组的最大和都为dp[i-1]+nums[i],如果dp[i-1]<0,无论nums[i]是什么数,以nums[i]为结尾的连续子数组的最大和都为nums[i...
Given an integer array, find a subarray with sum closest to zero. Return the indexes of the first number and last number. Have you metthisquestion in a real interview?Yes Example Given [-3, 1, 1, -3, 5],return[0, 2], [1, 3], [1, 1], [2, 2] or [0, 4]. ...
Count Numbers with Unique Digits wisdompeak 93 0 12:29 【LeetCode】930. Binary Subarrays With Sum wisdompeak 241 0 30:09 【LeetCode】1882. Process Tasks Using Servers wisdompeak 89 0 18:07 【LeetCode】300. Longest Increasing Subsequence wisdompeak 227 0 ...
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Q1: Is Kadane's algorithm suitable for finding the maximum sum of a non-contiguous subarray? Ans: No, Kadane's algorithm is only suitable for finding the maximum sum of a contiguous subarray. Q2: Can Kadane's algorithm handle arrays with negative numbers? Ans: Yes, Kadane's algorithm can...
Given an integer array, find a subarray where the sum of numbers is zero. Your code should return the index of the first number and the index of the last number. Example Given [-3, 1, 2, -3, 4], return [0, 2] or [1, 3]. ...