#defineMAX_DIR 4classSolution{// UP, RIGHT, DOWN, LEFTintdir[MAX_DIR+1] = {-1,0,1,0,-1};intgetIndex(inti){if(i==1)return1;//RIGHT =1elseif(i==2)return3;//LEFT = 3elseif(i==3)return2;// DOWN = 2return0;// UP =0}public:intminCost(vector<vector<int>>& grid){int...
迷宫的例子实在太蠢了,我们来看一道大名鼎鼎的Word Ladder.我本人在面Ziillow Onsite时候碰到了原题分享一下我的代码(30行 击败97%的C++solution哈哈): intladderLength(stringbeginWord,stringendWord,vector<string>&wordDict){unordered_set<string>word_dict_;for(auto&word:wordDict)word_dict_.insert(word);if...
class Solution: """ @param: start: a string @param: end: a string @param: dict: a set of string @return: An integer """ def ladderLength(self, start, end, dict): dict.add(end) q = [start] visited = set([start]) distance = 0 while q: distance += 1 new_q = [] for wo...
dp[i] = dp[i-1] + conver[i] classSolution{funfindPrefixScore(nums:IntArray):LongArray{valn=nums.sizevalret=LongArray(n)// 初始状态ret[0]=2L*nums[0]varmaxNum=nums[0]// DPfor(iin1until n){maxNum=Math.max(maxNum,nums[i])ret[i]=ret[i-1]+(0L+nums[i]+maxNum)}returnret}}...
非常可乐 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 14153 Accepted Submission(s): 5653 Problem Des...
a.List the sequence of vertices visited by depth-first search, starting at the point A.When multiple vertices can be chosen to be visited at a given time, settle the tie by visiting the vertex that comes first alphabetically. Each vertex...
For example, truncate(8.345) = 8 & truncate(-2.7335) = -2. Note: Assume we are dealing with an environment that could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For this problem, assume that your function returns 231 − 1 when the division ...
Example 2: Input: [ [1,1] ] Output: 1 ` classCoordinate{intx;inty;publicCoordinate(intx,inty){this.x = x;this.y = y; } }publicclassSolution{/** *@paramgrid: a boolean 2D matrix *@return: an integer */int[] deltaX = {0,1,-1,0};int[] deltaY = {1,0,0,-1};publicin...
* Example: * var ti = TreeNode(5) * var v = ti.`val` * Definition for a binary tree node. * class TreeNode(var `val`: Int) { * var left: TreeNode? = null * var right: TreeNode? = null * } */ class Solution {
where the only legal operation is to exchange 'x' with one of the tiles with which it shares an edge. As an example, the following sequence of moves solves a slightly scrambled puzzle: 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 ...