n 皇后问题研究的是如何将 n 个皇后放置在 n×n 的棋盘上,并且使皇后彼此之间不能相互攻击。 上图为 8 皇后问题的一种解法。 给定一个整数 n,返回所有不同的 n 皇后问题的解决方案。 每一种解法包含一个明确的 n 皇后问题的棋子放置方案,该方案中 'Q' 和 '.' 分别代表了皇后和空位。 示例: 输入: 4...
Two solutions You can use an associative map again: Live std::map<V, int> distances; auto vis = make_bfs_visitor(record_distances( boost::make_assoc_property_map(distances), boost::on_tree_edge{})); You can fix the propertymap by projecting the key through the temporary vertex ...
BFS and DFS, both of the graph searching techniques have similar running time but different space consumption, DFS takes linear space because we have to remember single path with unexplored nodes, while BFS keeps every node in memory. DFS yields deeper solutions and is not optimal, but it work...